On Tue, Apr 23, 2013 at 03:41:18PM +0400, Dmitry Monakhov wrote:
> The only guess I have is that this is a miss typo because buffer
> is busy if some one hold an reference (bh->b_count !=0 ) ||
> it is (dirty | locked). So following patch
... is pointless. All callers only care about the return
Hi,
Can anyone please justify me the logic of fs/bufferc.c:buffer_busy()
How can we perform bit-wise operation for ->b_count and ->b_state?
static inline int buffer_busy(struct buffer_head *bh)
{
return atomic_read(&bh->b_count) |
(bh->b_state & ((1 << BH_Dirty) | (1 << BH
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