Re: [linux-programming] bash scripting; array

2006-08-16 Terurut Topik riza x
On Mon, 2006-08-14 at 07:56 +0100, ANTON CHANG wrote: > --- riza x <[EMAIL PROTECTED]> wrote: > terima kasih, hasil akhir dapat di lihat di: http://rizahnst.afraid.org/2006/08/14/more-on-variables-array/ > > #!/bin/bash > # > # display_it.sh > # This script will display... err..well, im not fi

Re: [linux-programming] bash scripting; array

2006-08-13 Terurut Topik ANTON CHANG
--- riza x <[EMAIL PROTECTED]> wrote: > On Sun, 2006-08-13 at 14:05 +1000, Johannes Sasongko > wrote: > > > #!/bin/bash > > > # > > > # display_it.sh > > > # This script will display... err..well, im not > finish it yet :) > > > > > > declare -a ARGM > > > > > > echo "This script you are using is

Re: [linux-programming] bash scripting; array

2006-08-13 Terurut Topik riza x
On Sun, 2006-08-13 at 14:05 +1000, Johannes Sasongko wrote: > > #!/bin/bash > > # > > # display_it.sh > > # This script will display... err..well, im not finish it yet :) > > > > declare -a ARGM > > > > echo "This script you are using is: $0" | sed 's/.\///' > > echo "You passed $# argument(s)." >

Re: [linux-programming] bash scripting; array

2006-08-12 Terurut Topik Johannes Sasongko
#!/bin/bash # # display_it.sh # This script will display... err..well, im not finish it yet :) declare -a ARGM echo "This script you are using is: $0" | sed 's/.\///' echo "You passed $# argument(s)." while (( $# )); do echo $1 ARGM[$#]=$1; shift done echo "Your argument

[linux-programming] bash scripting; array

2006-08-11 Terurut Topik riza x
halo smua, saat ini saya sedang belajar bash scripting. pada salah satu tugas latihannya adalah tentang variable jenis array, http://www.tldp.org/LDP/Bash-Beginners-Guide/html/sect_10_05.html saya kesulitan dalam memanipulasi urutan data yang di masukkan ke dalam variable jenis array tersebut. s