On 1 Dec 2009, at 07:44, Ruud H.G. van Tol wrote:
Abigail wrote:
On Mon, Nov 30, 2009 at 06:24:12PM +, Chris Jack wrote:
7) Write a one line program that takes a non-negative integer as an argument
and prints the square root when the answer's an integer.
Restrictions: the perl line
On Tue, Dec 1, 2009 at 09:03, Mike Whitaker m...@altrion.org wrote:
(this is not an answer)
But this might be:
echo 169 | perl -pe '/(\d+)(?{ $_ = sqrt($^N).\n })/;'
Except it didn't follow the rules.
Cheers,
Philip
--
Philip Newton philip.new...@gmail.com
On Mon, Nov 30, 2009 at 02:52:21PM -0800, Avleen Vig wrote:
On Nov 30, 2009, at 14:43, Dave Hodgkinson daveh...@gmail.com wrote:
How many people will be mildly irritated by starting a new thread
with a Reply-to: to an existing one?
Answer: none. We stopped being petty in 1997 and grew up :p
On Mon, Nov 30, 2009 at 11:40:04PM +, Chris Jack wrote:
Abigail abig...@abigail.be wrote
On Mon, Nov 30, 2009 at 06:24:12PM +, Chris Jack wrote:
7) Write a one line program that takes a non-negative integer as an
argument
and prints the square root when the answer's
Forgive my ignorance on this one. I'm not a perl programmer. I was
assuming this was a perl/LUG meet. Does that sound about right? This will
be my first LUGish meeting.
Dan
On Mon, Nov 30, 2009 at 1:18 PM, Lesley Binks lesl...@pgcroft.net wrote:
On Sun, Nov 29, 2009 at 04:58:06PM +,
Avleen Vig wrote:
On Nov 30, 2009, at 14:43, Dave Hodgkinson daveh...@gmail.com wrote:
On 30 Nov 2009, at 18:24, Chris Jack wrote:
Seeing as last year's quiz was mildly popular,
Bonus question:
How many people will be mildly irritated by starting a new thread
with a Reply-to: to an
On Mon, Nov 30, 2009 at 10:43:19PM +, Dave Hodgkinson wrote:
Bonus question:
How many people will be mildly irritated by starting a new thread
with a Reply-to: to an existing one?
Not as many as will be mildly irritated at me replying but chopping out
the Reply-To.
--
David Cantrell |
7) Write a one line program that takes a non-negative integer as an
argument and prints the square root when the answer's an integer.
Restrictions: the perl line should be a regular expression.
You are allowed to use the following functions/operators x, -,
length, print plus any of
I recall that as part of technical test I took for a previous role, to
try and interpret and determine what it did. Quite cool, but the
coolness was definitely exceeded by it's evilness... :)
Mark.
On Tue, Dec 1, 2009 at 11:26 AM, Abigail abig...@abigail.be wrote:
which would be 'similar' but
On Mon, 30 Nov 2009 18:24:12 +, Chris Jack wrote:
1) Without running it to check, what does the following program output?
my %a = (3,2,1,0);
for my $b (sort values %a) {
$b += 4;
}
print $a{1} . \n;
Bizarrely enough, on both my Snow Leopard machines (default perl
On Tue, 1 Dec 2009 11:23:09 -0500, Matt Sergeant wrote:
On Mon, 30 Nov 2009 18:24:12 +, Chris Jack wrote:
1) Without running it to check, what does the following program output?
my %a = (3,2,1,0);
for my $b (sort values %a) {
$b += 4;
}
print $a{1} . \n;
Bizarrely
Matt == Matt Sergeant mserge...@messagelabs.com writes:
Matt On Mon, 30 Nov 2009 18:24:12 +, Chris Jack wrote:
1) Without running it to check, what does the following program output?
my %a = (3,2,1,0);
for my $b (sort values %a) {
$b += 4;
}
print $a{1} . \n;
Matt
2009/12/1 Matt Sergeant mserge...@messagelabs.com:
On Tue, 1 Dec 2009 11:23:09 -0500, Matt Sergeant wrote:
On Mon, 30 Nov 2009 18:24:12 +, Chris Jack wrote:
1) Without running it to check, what does the following program output?
my %a = (3,2,1,0);
for my $b (sort values %a) {
$b
On Tue, Dec 1, 2009 at 17:52, Dermot paik...@googlemail.com wrote:
(not sure about this point) is a copy of the value in $a{1}.
That's the salient point - it's an alias to the value in $a{1}, rather
than a copy, since values %hash returns aliasses, sort just shuffles
those aliasses, and foreach
Dermot == Dermot paik...@googlemail.com writes:
Dermot My first impression was that it would be 4. However, without running
Dermot it, I would say 0 on the basis that $b is scoped within the loop and
Dermot (not sure about this point) is a copy of the value in $a{1}.
That's the nice thing
On 12/01/2009 04:52 PM, Dermot wrote:
2009/12/1 Matt Sergeantmserge...@messagelabs.com:
On Tue, 1 Dec 2009 11:23:09 -0500, Matt Sergeant wrote:
On Mon, 30 Nov 2009 18:24:12 +, Chris Jack wrote:
1) Without running it to check, what does the following program output?
my %a = (3,2,1,0);
2009/12/1 Philip Newton philip.new...@gmail.com:
On Tue, Dec 1, 2009 at 17:52, Dermot paik...@googlemail.com wrote:
(not sure about this point) is a copy of the value in $a{1}.
That's the salient point - it's an alias to the value in $a{1}, rather
than a copy, since values %hash returns
Matt == Matt Sergeant mserge...@messagelabs.com writes:
Matt Yes. Though oddly enough it doesn't show up in the same terminal when
Matt ssh'd into a Linux box. I'd like to know the reason why that is.
Maybe linux doesn't echo the ^D as uparrow D?
Or maybe linux adds a newline after it?
Dunno.
On Tue, 01 Dec 2009 08:47:55 -0800, Randal L. Schwartz wrote:
Lemme guess. You did this:
$ perl
... type program in here ...
^D (control D)
The D is from your control D.
Common misconception.
Yes. Though oddly enough it doesn't show up in the same terminal when
ssh'd into a Linux
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