Re: [lustre-discuss] 8TiB LDISKFS MDT

2019-10-15 Thread Tamas Kazinczy
On 2019. 10. 15. 17:31, Mohr Jr, Richard Frank wrote: On Oct 15, 2019, at 9:52 AM, Tamas Kazinczy wrote: With defaults (1024 for inode size and 2560 for inode ratio) I get only 4,8T usable space. With those values, an inode is created for every 2560 bytes of MDT space. Since the inode is 10

Re: [lustre-discuss] 8TiB LDISKFS MDT

2019-10-15 Thread Mohr Jr, Richard Frank
> On Oct 15, 2019, at 9:52 AM, Tamas Kazinczy > wrote: > > With defaults (1024 for inode size and 2560 for inode ratio) I get only 4,8T > usable space. With those values, an inode is created for every 2560 bytes of MDT space. Since the inode is 1024 bytes, that leaves (2560 - 1024) = 1536

[lustre-discuss] 8TiB LDISKFS MDT

2019-10-15 Thread Tamas Kazinczy
Hi, what is the proper way of creating an MDT with LDISKFS if my device is 8TiB? I've already tried several combinations of inode size and inode ratio. With defaults (1024 for inode size and 2560 for inode ratio) I get only 4,8T usable space. Increasing inode ratio gives more usable space up