On 10/08/2022 16:34, Stefan Behnel wrote:
Gilles schrieb am 10.08.22 um 15:20:
for row in tree.iter("wpt"):
lat,lon = row.attrib.values()
Note that this assignment depends on the order of the two attributes
in the XML document, i.e. in data that you may not control yourself.
It will bre
Gilles schrieb am 10.08.22 um 15:20:
for row in tree.iter("wpt"):
lat,lon = row.attrib.values()
Note that this assignment depends on the order of the two attributes in the
XML document, i.e. in data that you may not control yourself. It will break
if the provider of your input documents
On 10/08/2022 13:30, Charlie Clark wrote:
Yes, this should work. However, I don't know if adjusting the tree
while looping over it won't the same kind of problems as with other
sequences in Python.
How many elements are there in your tree? Memory use in XML can get very
expensive so combining
On 10 Aug 2022, at 9:53, Gilles wrote:
> An important line was missing :-/
>
> no_dups = {}
>
> for row in tree.iter("wpt"):
>
> name,lat,lon = [row.find("name").text] + row.attrib.values()
>
> if name not in no_dups:
>
> no_dups[name] = lat,lon
>
> else:
>
> #dup = rem
An important line was missing :-/
no_dups = {}
for row in tree.iter("wpt"):
name,lat,lon = [row.find("name").text] + row.attrib.values()
if name not in no_dups:
no_dups[name] = lat,lon
else:
#dup = remove
row.getparent().remove(row)
On 09/08/2022 20:59, Gilles
