Re: [M100] OptRom Exit Question

2019-09-11 Thread Kurt McCullum
I see now that it is actually 7 bytes The first 3 bytes jump to F991 which is the location in ram with the code to turn the OptRom on. That returns to the next 3 bytes which call to the OptRom routine. OptRom exits and the last byte is a RET. I have it working right now where I just poke the 7 b

Re: [M100] OptRom Exit Question

2019-09-11 Thread Stephen Adolph
how permanently protected does the 6 byte hole need to be? presume the RAM must contain opcodes and not just data? a commonly used place is "Hayash"...thats 6 bytes On Wed, Sep 11, 2019 at 10:49 AM Kurt McCullum wrote: > Got the code working properly but this leads to another question. I am in

Re: [M100] OptRom Exit Question

2019-09-11 Thread Kurt McCullum
Got the code working properly but this leads to another question. I am in search of 6 bytes of RAM. I used the same idea behind TS-DOS when the DOS-ON feature is used. That inserts 6 bytes of code that calls the OptRom ON routine and then jumps to the specific section of the Option ROM. When tha