On 10/7/21 2:35 PM, McGuire, Tommy M. (MSFC-IS90)[EAST2] via Mailman-Users wrote:
Suppose you have two lists: sou...@example.com and destinat...@example.com and 
that you want destination to be subscribed to source. In addition to making 
destination a member of source (so source sends email to destination), what do 
you need to put as a non-member in destination?

Should it be 'sou...@example.com' or 'source-boun...@example.com'?

Email that source sends out has a from address of "source-bounces@..." but is the 
"-bounces" stripped off before the moderation processing?

Yes, I'm trying to figure out why one particular sub-list isn't getting email.


These questions are answered at https://wiki.list.org/x/4030574 but there's more to it than that.

If sou...@example.com has only other lists as members, it should be defined as an umbrella list by setting General Options -> umbrella_list to Yes. Without this, one can send a message with

Subject: password address=destinat...@example.com

to source-requ...@example.com and the password for destinat...@example.com will be sent to that list. Setting umbrella_list to Yes will send such notices to destination-ow...@example.com, but if the sou...@example.com list has human members as well, this will mess up notices to them.

Also see https://wiki.list.org/x/4030540 for info about how to use Non-digest options -> regular_include_lists as an alternative.

--
Mark Sapiro <m...@msapiro.net>        The highway is for gamblers,
San Francisco Bay Area, California    better use your sense - B. Dylan
------------------------------------------------------
Mailman-Users mailing list -- mailman-users@python.org
To unsubscribe send an email to mailman-users-le...@python.org
https://mail.python.org/mailman3/lists/mailman-users.python.org/
Mailman FAQ: http://wiki.list.org/x/AgA3
Security Policy: http://wiki.list.org/x/QIA9
Searchable Archives: https://www.mail-archive.com/mailman-users@python.org/
   https://mail.python.org/archives/list/mailman-users@python.org/

Reply via email to