Thanks to all who gave me reason to believe (as I should I done it) there is
nothing wrong with the mid$() function. It was a problem due to the way I
was calculating the arguments, by increments that I thought would end up to
the string length but in fact exceeded it.
I rediscovered the very old s
= 29700
print "j (smallint) = "+j
print "Mid$(BigString, j, 10) = "+chr$(34)+Mid$(BigString, j,
10)+chr$(34)
end sub
' End
-Original Message-
From: Jacques Paris [mailto:[EMAIL PROTECTED]
Sent: 20 November 2003 22:49
To: MIL
Subject: MI-L limit in mid$()
The length of a string variable into which I read the record of a file is of
32766. I use the mid$() function to extract bits and pieces. When the start
parameter (second argument) reaches 29696, there is an error message
"Overflow Mid$; argument 2 has invalid type". As the same formula has worked
