John Hunter schrieb:
>> Second, I am using interactive mode and WXAgg in windows. So my startup
>> script does this:
>> import matplotlib as _mpl
>> _mpl.use('WXAgg')
>> import pylab as _p
>> _p.ion()
>> Before, when I would then type
>> gca().plot([1,2,1])
>>
>
> I would not expect a draw her
On Tue, Sep 16, 2008 at 2:14 PM, Jack Sankey <[EMAIL PROTECTED]> wrote:
> Hello,
> I couldn't find this in the API changes, but when I upgraded to the latest
> matplotlib 0.98.2, I found (after much hair pulling) that
> gca().plot([1,2,1], label='_anything')
> will produce a plot and
> gca().legend
Hello,
I couldn't find this in the API changes, but when I upgraded to the latest
matplotlib 0.98.2, I found (after much hair pulling) that
gca().plot([1,2,1], label='_anything')
will produce a plot and
gca().legend()
will not display the specified label. I had been using filenames starting
wit
