Dear colleagues,
Is there a artist function or routine available in matplotlib for drawing
animated arrows following lines (like streamplot) in a 2D space, or even
better in a 3D space?
Thanks in advance for any hint, or sample code.
Regards,
Claude
Claude Falbriard
Certified IT Special
On 2014/04/24 11:40 PM, Tom Grydeland wrote:
> Hi all,
>
> I will explain what I’m trying to achieve first, then the approaches I’ve
> attempted so far, with results.
>
> I have data on a 2D grid which I want to present as an image — a la
> pyplot.imshow() — except that the grid is hexagonal, not
Nathan,
Thanks for bringing this up. It looks like the short-term fix is to
make the documentation match the code. Longer term, it seems to me like
this is the sort of thing that should be deprecated; it doesn't belong
in matplotlib any more.
Would you open an issue on Github, please? Even
You might have more luck reading in that data (dates with mixed format)
with pandas than numpy.
On Fri, Apr 25, 2014 at 2:37 AM, Mark Bakker wrote:
> Thanks, Andreas, but it doesn't quite work.
>
> This works for me (I manually changed all dates to 'day-month-year' for
> testing):
>
> a = load
Hello,
I have been using the matplotlib.mlab.entropy function and have noticed that it
may be incorrect. I have posted a question on stackoverflow here:
http://stackoverflow.com/questions/23291576/matplotlib-mlab-entropy-calculation-incorrect
I thought I would should it on the mailing list too.
Hi all,
I will explain what I’m trying to achieve first, then the approaches I’ve
attempted so far, with results.
I have data on a 2D grid which I want to present as an image — a la
pyplot.imshow() — except that the grid is hexagonal, not rectangular. The grid
can be represented in multiple w
Thanks, Andreas, but it doesn't quite work.
This works for me (I manually changed all dates to 'day-month-year' for
testing):
a = loadtxt('test.csv',converters={2:strpdate2num('%d-%m-%Y')})
But when I define the same function in a separate function, as you
suggested:
def conv_date(s):
retu
On 25.04.2014 11:02, Mark Bakker wrote:
> OK, I figured out I can use:
> converters={0:strpdate2num('%d-%m-%y')}
>
> What now if part of my dates are given as 'day-month-year' and part as
> 'day/month/year' in the same file (I know, who does that, an I could do
> a replace first and then read it i
OK, I figured out I can use:
converters={0:strpdate2num('%d-%m-%y')}
What now if part of my dates are given as 'day-month-year' and part as
'day/month/year' in the same file (I know, who does that, an I could do a
replace first and then read it in). Can I specify both formats for the
converter? I
Hello List,
datestr2num works great when dates are stored as month/day/year (as
American like).
Europeans store them as day/month/year.
Any quick function to convert a day/month/year string do a date? Is there
an eu version: datestr2numeu?
Thanks,
Mark
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