But what about 8? It's factors are 1 and 8 and 2 and 4. That doesn't work
too well.
8 = 3 + 5 : 3 is prime 5 is prime. Q. E. D.
other examples:
4 = 2 + 2
6 = 3 + 3
8 = 5 + 3
10 = 5 + 5 = 3 + 7
etc . . .
I believe what we are talking about here is Goldbach's Conjecture. To date
(to my
At 07:51 PM 11/13/98 -0800, William Stuart wrote:
Another interesting thing about this conjecture...
If it is correct, then there is no last prime.
And if Goldbach's conjecture is incorrect - then there is no last prime!
+--+
| Jud
At 07:51 PM 11/13/98 -0800, William Stuart wrote:
Another interesting thing about this conjecture...
If it is correct, then there is no last prime.
There's no last prime anyways. This is Euclid's Theorem and was proven
thousands of years ago, as follows:
Let p1, p2, ... , pn be a finite
Ok, let's see.
3x2=6
But what about 8? It's factors are 1 and 8 and 2 and 4. That doesn't work
too well.
Jon
I ran across an interesting statement on the top of a math paper that I
was helping my sister with. It said that every even number greater than 4
is the sum of two primes. I am
I'm sure that it probably has been done, however, I am considering writing
a program to see if I can disprove this theorem. It is my belief that it
can be disproven because the higher you go, the less primes you have.
Anyway, writing the program will be challenging and give me something to
do.
Try http://www.utm.edu/research/primes/notes/conjectures/ for a list of
interesting conjectures including this one.
Steve Gardner
[EMAIL PROTECTED]
Check out 84000 computer products at
www.pcavenue.com
-Original Message-
From: Aaron Cannon [EMAIL PROTECTED]
To: [EMAIL PROTECTED] [EMAIL
At 8:51 PM -0500 11/13/98, [EMAIL PROTECTED] wrote:
No, not factors. The different addends of the number.
4 = 2 + 2 (2 is prime)
6 = 3 + 3 (3 is prime)
8 = 3 + 5 (both prime)
10 = 5+5
12 = 5+7
14=7+7
16=5+11
18=7+11
Well, you get the idea. Another interesting thing to note which is part of
the
