Hi Josh,
Yes maybe it could be done with plain old CSS...I'll have a think.
In the meantime I wrote the following filter:
@register.filter(name='comment_level')
def
comment_level(comment):
'''
Takes a comment and returns its level in the tree.
Parent comments are not replies to anything and have level
0.
'''
level =
0
while
True:
if not
comment.replied_to:
# comment is not a reply, but a level 0
parent.
break
else:
# comment is a reply, inc level
+1
level +=
1
# move to comment
above
comment =
comment.replied_to
# at end of recursion, return the
level
return level
So now in my template I can get the comment level in the tree with {{
comment|comment_level}}....not sure if this function is particularly
efficient, or if there is a much simpler way though. Maybe it will be
useful for something else later....
I also realised I could test if a given comment had any children with
{% if comment.id in all_comments|defaultdict_keys %}
(I had to use the filter `defaultdict_keys` that just returns
`all_comments.keys()` instead of just calling .keys as normal, since this
is a defaultdict not a dict. The problem is django tries
all_comments['keys'] first when .keys is called on a dict in a template,
and this being a defaultdict(list) is obliges with [] giving an empty list
for the keys even when dict is full)
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