Hello,
Sorry about non mod_perl question, but as I'm subscribed to this list and
I know I can get help from here, I ask my question here.
Can anyone tell me, what's wrong with this piece of code:
$vars-{'key2'} = value of second key;
$vars = {
xxx = AAA,
yyy = BBB,
zzz = CCC,
};
On Fri, 17 May 2002 17:10:53 +0300 (EEST)
Viljo Marrandi [EMAIL PROTECTED] wrote:
: $vars-{'key2'} = value of second key;
The hash $vars points to has a key named key2.
: $vars = {
: xxx = AAA,
: yyy = BBB,
: zzz = CCC,
: };
Now you change the reference stored in $var. It points
Viljo Marrandi wrote:
Sorry about non mod_perl question, but as I'm subscribed to this list and
I know I can get help from here, I ask my question here.
Please do NOT do that in the future. This is the *modperl* list. There
are hundreds of perl lists which will gladly help you out.
Stas Bekman wrote:
I know I don't sound nice, but we try hard to keep a low Sound to Noise
Ratio here.
of course I meant a *high* Sound to Noise Ratio. the heat and humidity
shows :)
p.s. sorry for adding to the noise. back to work on adding more sound.
In support of F. Xavier Noria, and in simpler terms - your $vars = {
. } overwrote your previous assignment of $vars-{'key2'}.
Perhaps you could have done:
my $var = {};
$var-{'key2'} = some value;
my @args = qw/ XXX YYY ZZZ /;
my @vals = qw/ AAA BBB CCC /;
my $i;
for ($i =0; $i
At 16:10 17.05.2002, Viljo Marrandi wrote:
Hello,
Sorry about non mod_perl question, but as I'm subscribed to this list and
I know I can get help from here, I ask my question here.
Can anyone tell me, what's wrong with this piece of code:
$vars-{'key2'} = value of second key;
$vars = {
