On Thu, 4 May 2000, Jeffrey W. Baker wrote:
Not strictly for debugging, but for introspection. I was toying with
a module that pokes around inside the perlguts of a running mod_perl
server and makes some nice displays out of them. Nothing for
production/money mind you, just amusement.
On Wed, 3 May 2000, Jeffrey W. Baker wrote:
Apache::print() dereferences its arguments. For example, this code:
my $foo = "bar";
$r-print(\$foo);
prints "bar" instead of the expected SCALAR(0xDEADBEEF). Can anyone
explain the purpose of this behavior, or is it a misfeature? In my
On Wed, 3 May 2000, Doug MacEachern wrote:
On Wed, 3 May 2000, Jeffrey W. Baker wrote:
Apache::print() dereferences its arguments. For example, this code:
my $foo = "bar";
$r-print(\$foo);
prints "bar" instead of the expected SCALAR(0xDEADBEEF). Can anyone
explain the
Apache::print() dereferences its arguments. For example, this code:
my $foo = "bar";
$r-print(\$foo);
prints "bar" instead of the expected SCALAR(0xDEADBEEF). Can anyone
explain the purpose of this behavior, or is it a misfeature? In my case,
this is not the desired behavior.
-jwb
On Wed, 3 May 2000, Jeffrey W. Baker wrote:
Apache::print() dereferences its arguments. For example, this code:
my $foo = "bar";
$r-print(\$foo);
prints "bar" instead of the expected SCALAR(0xDEADBEEF). Can anyone
explain the purpose of this behavior, or is it a misfeature? In my
"Jeffrey W. Baker" [EMAIL PROTECTED] writes:
Apache::print() dereferences its arguments. For example, this code:
my $foo = "bar";
$r-print(\$foo);
prints "bar" instead of the expected SCALAR(0xDEADBEEF). Can anyone
explain the purpose of this behavior, or is it a misfeature? In my
"Jeffrey" == Jeffrey W Baker [EMAIL PROTECTED] writes:
Jeffrey Apache::print() dereferences its arguments. For example, this code:
Jeffrey my $foo = "bar";
Jeffrey $r-print(\$foo);
Jeffrey prints "bar" instead of the expected SCALAR(0xDEADBEEF). Can anyone
Jeffrey explain the purpose of this
03, 2000 1:37 PM
To: [EMAIL PROTECTED]
Subject: Why does $r-print() dereference its arguments?
Apache::print() dereferences its arguments. For example, this code:
my $foo = "bar";
$r-print(\$foo);
prints "bar" instead of the expected SCALAR(0xDEADBEEF). Can anyone
]
Subject: Why does $r-print() dereference its arguments?
Apache::print() dereferences its arguments. For example, this code:
my $foo = "bar";
$r-print(\$foo);
prints "bar" instead of the expected SCALAR(0xDEADBEEF). Can anyone
explain the purp
-Original Message-
From: Stas Bekman [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, May 03, 2000 2:07 PM
To: Geoffrey Young
Cc: mod_perl list
Subject: RE: Why does $r-print() dereference its arguments?
On Wed, 3 May 2000, Geoffrey Young wrote:
interesing behavior - print
-Original Message-
From: Stas Bekman [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, May 03, 2000 2:23 PM
To: Geoffrey Young
Cc: mod_perl list
Subject: RE: Why does $r-print() dereference its arguments?
-Original Message-
From: Stas Bekman [mailto:[EMAIL PROTECTED
On 3 May 2000, Chip Turner wrote:
"Jeffrey W. Baker" [EMAIL PROTECTED] writes:
Apache::print() dereferences its arguments. For example, this code:
my $foo = "bar";
$r-print(\$foo);
prints "bar" instead of the expected SCALAR(0xDEADBEEF). Can anyone
explain the purpose of
At 11:56 AM 5/3/00 -0700, Jeffrey W. Baker wrote:
On 3 May 2000, Chip Turner wrote:
"Jeffrey W. Baker" [EMAIL PROTECTED] writes:
Apache::print() dereferences its arguments. For example, this code:
my $foo = "bar";
$r-print(\$foo);
prints "bar" instead of the expected
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