On Tue, 2009-09-01 at 23:50 -0400, Chris Prather wrote:
Okay since I started beating people about the head and shoulders that
we're an open process
(http://chris.prather.org/perl/take-arms-against-a-sea-of-troubles/)
what do we need to get the current outstanding branches in Moose.git
(and
So, when next I have a dose of free time (which hopefully will be
later this month) I want to revise the Moose website. As Gabor pointed
out (http://szabgab.com/blog/2009/08/1251583673.html), what is there
now is not very organized and difficult to wade through. As Moose gets
more popular
On Thu, 3 Sep 2009, Stevan Little wrote:
I am not looking for sponsorship, endorsement or anything official, just like
to be able to point out to people who ask (like this guy on perlmonks -
http://www.perlmonks.org/index.pl?node_id=793076). Here is a short list of
companies I already know
On Sep 3, 2009, at 4:25 PM, Dave Rolsky wrote:
On Thu, 3 Sep 2009, Stevan Little wrote:
I am not looking for sponsorship, endorsement or anything official,
just like to be able to point out to people who ask (like this guy
on perlmonks - http://www.perlmonks.org/index.pl?node_id=793076).
We're using moose at Napster to rewrite a bit of our backend, and I'm
pushing for it elsewhere. In fact, today we just rolled out the list
of dependencies and the latest moose version to our frontend so (after
a year) I'm finally getting somewhere.
On Thu, Sep 3, 2009 at 1:25 PM, Dave
On Thu, 3 Sep 2009, Stevan Little wrote:
On Sep 3, 2009, at 4:25 PM, Dave Rolsky wrote:
On Thu, 3 Sep 2009, Stevan Little wrote:
I am not looking for sponsorship, endorsement or anything official, just
like to be able to point out to people who ask (like this guy on perlmonks
-
If I say isa = 'Class', then it will include all derived classes.
How do I exclude derived classes?
Do I need a subtype like:
subtype TopClassOnly = as 'Class' = where {blessed($_) eq 'Class'};
--
Yuri
On Thu, Sep 03, 2009 at 01:33:58PM -0700, Yuri Shtil wrote:
If I say isa = 'Class', then it will include all derived classes.
How do I exclude derived classes?
Do I need a subtype like:
subtype TopClassOnly = as 'Class' = where {blessed($_) eq 'Class'};
First of all, don't do that, and
On Thu, Sep 3, 2009 at 3:45 PM, Stevan
Littlestevan.lit...@iinteractive.com wrote:
So, when next I have a dose of free time (which hopefully will be later this
month) I want to revise the Moose website. As Gabor pointed out
(http://szabgab.com/blog/2009/08/1251583673.html), what is there now is
On Sep 3, 2009, at 5:04 PM, Chris Prather wrote:
On Thu, Sep 3, 2009 at 3:45 PM, Stevan
Littlestevan.lit...@iinteractive.com wrote:
So, when next I have a dose of free time (which hopefully will be
later this
month) I want to revise the Moose website. As Gabor pointed out
I missed the list ... why doesn't google to reply to all anymore? *sigh*
-- Forwarded message --
From: Chris Prather perig...@gmail.com
Date: Thu, Sep 3, 2009 at 5:10 PM
Subject: Re: Specifying exact type
To: Jesse Luehrs d...@tozt.net
On Thu, Sep 3, 2009 at 4:41 PM, Jesse
Excerpts from Yuri Shtil's message of Thu Sep 03 19:08:17 -0400 2009:
What is wrong in excluding some of the derived classes from a subtype
definition?
Like Chris said:
One of the main points to object orientation is Subtype Polymorphism
... meaning derived classes can be substituted for
subtype Foo, as ArrayRef[Str], where { @$_ 5 };
Foo is now a parameteriz*able* type, not a parameteriz*ed* type; that is,
in theory (if the MooseX::Types decorators allow it), you can:
has foo_classes = (isa = Foo[ClassName]);
since ClassName is a subtype of Str.
This surprised me, and
Excerpts from Hans Dieter Pearcey's message of Thu Sep 03 20:52:02 -0400 2009:
subtype Foo, as ArrayRef[Str], where { @$_ 5 };
Foo is now a parameteriz*able* type, not a parameteriz*ed* type; that is,
in theory (if the MooseX::Types decorators allow it), you can:
has foo_classes =
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