Re: Z80 T-States

2000-04-07 Thread Alex Wulms
] ] ] Is it true that every Z80 instruction on a MSX takes ] one extra T-State because of a delay caused by ] the MSX Engine ? Yes indeed. ] In other words, a NOP instructions takes 4 T-States, ] but in a real MSX it would take 5 T-States. This is correct. Kind regards, Alex Wulms -- Visit

RE: Z80 T-States

2000-04-05 Thread Hans Otten
n the Redbook?). Hans -Original Message- From: Frits Hilderink [mailto:[EMAIL PROTECTED]] Sent: 05 April 2000 16:15 To: [EMAIL PROTECTED] Subject: Z80 T-States Is it true that every Z80 instruction on a MSX takes one extra T-State because of a delay caused by the MSX Engine ? In other

Re: Z80 T-States

2000-04-05 Thread Ricardo Bittencourt Vidigal Leitao
On Wed, 5 Apr 2000, Frits Hilderink wrote: > Is it true that every Z80 instruction on a MSX takes > one extra T-State because of a delay caused by > the MSX Engine ? Yes it is. If this wasn't true, then the pitch on the voices produced by BrMSX would be lower, since BrMSX emulate

Z80 T-States

2000-04-05 Thread Frits Hilderink
Is it true that every Z80 instruction on a MSX takes one extra T-State because of a delay caused by the MSX Engine ? In other words, a NOP instructions takes 4 T-States, but in a real MSX it would take 5 T-States. Frits MSX Mailinglist. To unsubscribe, send an email to [EMAIL PROTECTED