Re: [music-dsp] high & low pass correlated dither noise question

2019-06-27 Thread Ethan Duni
So as Nigel and Robert have already explained, in general you need to separately handle the spectral shaping and pdf shaping. This dither algorithm works by limiting to the particular case of triangular pdf with a single pole at z=+/-1. For that case, the state of the spectral shaping filter can be

Re: [music-dsp] high & low pass correlated dither noise question

2019-06-27 Thread robert bristow-johnson
  Original Message Subject: [music-dsp] high & low pass correlated dither noise question From: "Alan Wolfe" Date: Thu, June 27, 2019 7:42 am To: "A discussion list for music-related DSP"

Re: [music-dsp] ADC'19 Call for Proposals

2019-06-27 Thread Jean-Baptiste Thiebaut
Hi, The deadline for sending proposals for ADC is tomorrow, hope to see many of you in person in London next Fall! Best regards, JB > On 3 May 2019, at 11:01, Jean-Baptiste Thiebaut > wrote: > > Hi everyone, > > We are delighted to invite you to attend and contribute t

Re: [music-dsp] high & low pass correlated dither noise question

2019-06-27 Thread Nigel Redmon
> Rolling one die at a time, or two, Read: Rolling one die at a time, OF two, > On Jun 27, 2019, at 9:00 AM, Nigel Redmon wrote: > > I think this becomes more obvious if you separate out the random and the > filtering: > > Rolling one die at a time, or two, is equivalent to rolling one die, b

Re: [music-dsp] high & low pass correlated dither noise question

2019-06-27 Thread Nigel Redmon
I think this becomes more obvious if you separate out the random and the filtering: Rolling one die at a time, or two, is equivalent to rolling one die, but writing down or remembering the previous value before the roll. In there words, it’s like a like having a delay element to use for the sum

[music-dsp] high & low pass correlated dither noise question

2019-06-27 Thread Alan Wolfe
I read a pretty cool article the other day: https://www.digido.com/ufaqs/dither-noise-probability-density-explained/ It says that if you have two dice (A and B) that you can roll both dice and then... 1) Re-roll die A and sum A and B 2) Re-roll die B and sum A and B 3) Re-roll die A and sum A and