Hi All,
In this case how the images of a book will be stored, a chapter may contain
number of images with different size.
Or It deals only text?
Thanks.
Vikram A
From: Jerry Schwartz
To: Andy ; mysql@lists.mysql.com
Sent: Fri, 11 June, 2010 9:05:26 PM
Subje
[Top-post.]
You'll probably have much better luck on the MySQL General list.
CC'ed on this email.
On Tue, Jun 15, 2010 at 20:58, Jan Reiter wrote:
> Hi folks!
>
> I'm kind of ashamed to ask a question, as I haven't followed this list very
> much lately.
>
>
>
> This isn't exactly a PHP
Steven,
On Tue, Jun 1, 2010 at 11:15 AM, Steven Staples wrote:
> Hello all
>
> I have a stored procedure that probably does a lot more than it should, but
> it works fine on my test server (which is running 5.0.67). When I moved it
> over to the production server, (which is running 5.0.32 and I
[snip]
I have a table similar to this:
-
|transactions |
|ID |DATE |EMPLOYEE|
|234 |2010-01-05| 345|
|328 |2010-04-05| 344|
|239 |2010-01-10| 344|
Is there a way to query such a table to give the days of the year that
employee 344 did not
Hi Richard,
This is a LEFT JOIN, but with only one table you may be wondering what to join.
Typically you'll have to create a new table that contains all the dates in the
range you want to check. Then you left join your transaction table, and all
the rows from your dates table that don't have
I have a table similar to this:
-
|transactions |
|ID |DATE |EMPLOYEE|
|234 |2010-01-05| 345|
|328 |2010-04-05| 344|
|239 |2010-01-10| 344|
Is there a way to query such a table to give the days of the year that employee
344 did not have
can u please tell me , 5NF with example,
There's one in
http://www.artfulsoftware.com/mysqlbook/sampler/mysqled1ch01.html
PB
-
On 6/14/2010 10:51 PM, bharani kumar wrote:
Frankly speaking ,
Am looking very simple example for 5NF ,
Even i looked the lot of site , in most of the site t
Hi Brian, all!
brian wrote:
> On 10-06-14 09:13 PM, brian wrote:
>> [[...]]
>>
>> This not only gives an empty set, but also throws 171 warnings (more on
>> that below). I've remove both the WHERE and GROUP BY clauses with no
>> success. I've been staring at this for an hour now and can't see wha
