Hi Rafal,
binary is a reserved word, you need to quote it with back-ticks ` if
you want to use it:
SELECT s2u.valus as `binary`
FROM ...
/Johan
Rafal Kedziorski wrote:
Hi,
I get this:
You have an error in your SQL syntax. Check the manual that
corresponds to your MySQL server version for the
Hi Joshua,
the BLOB or TEXT is stored separately from the row. What is stored is
a pointer to where the BLOB/TEXT is located.
/Johan
Joshua Beall wrote:
Hi All,
I am a bit confused by the MySQL documentation on this subject. From
http://dev.mysql.com/doc/mysql/en/Storage_requirements.html
The
Hi,
you might take a look at this thread:
http://lists.mysql.com/mysql/166184
/Johan
Hi,
I'm searching for a function that enables me to calculate the product of
a group of values, like SUM() does. MySQL server version is at least
4.0.14.
For example, a query like
SELECT id, PRODUCT(value) AS
Hi,
you could try:
SELECT tbl1.id
FROM tbl1
LEFT JOIN tbl2 ON tbl2.another_id = tbl1.id
WHERE tbl2.id IS NULL
/Johan
Manish wrote:
This should be simple but I am stuck here. I need to select rows from table
1, which do not have matching ID in table 2.
Say each table has 100 rows each, and 90 rows
Shaun,
when you add WHERE B.Project_ID = '10' you, in a way,
change your LEFT JOIN to an INNER JOIN.
You need to do it like:
LEFT OUTER JOIN Bookings B ON U.User_ID = B.Rep_ID AND B.Project_ID = '8'
/Johan
shaun thornburgh wrote:
Thanks for your reply,
This works great, but when I add a
Hi,
you can use:
SELECT COUNT(B.Booking_ID), User_Location
FROM Users U
LEFT JOIN Bookings B ON U.User_ID = B.User_ID
GROUP BY(U.User_Location);
/Johan
shaun thornburgh wrote:
Hi,
The following table produces a query that shows all bookings that user
has made and groups the number of bookings by
Hi Keith,
I think your problem comes down to the fact that IF() is a function
that must return one value, when you put in your '*' you might be
specifying more then one value to return.
/Johan
Keith wrote:
g'day,
Am having a bit of a problem with using IF. This is the error message I get:
-
stand for?
Is it something like limited or incorporated?
If yes, is this something related to the origin of MySQL?
I am a subscriber from Hong Kong.
Thanks.
mc.
--
Johan Hook, Pythagoras Engineering Group
- MailTo:[EMAIL PROTECTED]
- http
Hi Dirk,
from the excellent on-line manual:
http://dev.mysql.com/doc/mysql/en/SELECT.html
Columns selected for output can be referred to in ORDER BY and GROUP BY clauses
using column names, column aliases, or column positions. Column positions are
integers and begin with 1:
mysql SELECT
Hi Dirk,
you should be able to just add on ORDER BY Count after your groub clause.
/Johan
Dirk Bremer (NISC) wrote:
The following query produces the following results:
select job_coop as 'Job/Coop', count(*) as Count from queue group by
job_coop;
-- snip
Is there a way to use the ORDER BY
Assuming you want to order your arbitrary selection you could
do something like:
(SELECT t.Id FROM tab t LIMIT 10)
UNION ALL
(SELECT t.Id FROM tab t WHERE 1 0)
ORDER BY t.Id
/Johan
Harald Fuchs wrote:
In article [EMAIL PROTECTED],
Paul DuBois [EMAIL PROTECTED] writes:
At 18:51 +0200 4/21/04,
Hi,
I guess this is for a java.sql.PreparedStatement as the '?'
seem to indicate that.
LIMIT limits ;-) the number of rows retrieved,
i.e. LIMIT 10, 20 gives you 20 rows starting at row 20 in the
resultset and LIMIT 10 gives you the first 10 rows.
See: http://www.mysql.com/doc/en/SELECT.html
Hi,
if you are using 4.x or later you can use:
(select * from helpdesk where month(helpdesk.hdcreatedate) = 3)
UNION ALL
(select * from archived where month(archived.hdcreatedate) = 3)
LIMIT 0, 30;
/Johan
rmck wrote:
Hi
I have two tables in the same Db :
table 1:
helpdesk | CREATE TABLE
Hi,
you could try something like:
INSERT INTO articles_multi(article,author,text_ru,text_en )
SELECT e.article,e.authoer,r.text,e.text
FROM articles_en e, articles_ru r
WHERE e.article = r.article
AND e.author = r.article
/Johan
nullevent wrote:
Hello mysql,
I have two tables -
Hi Keith,
you can use:
pla.type IN ('1','2','3','4');
/Johan
Keith wrote:
is there any alternative to using OR for selecting between values?
ie: pla.type='1' OR pla.type='2' OR pla.type='3' OR pla.type='4'
Cheers,
Keith
--
Johan Höök, Pythagoras Engineering Group
-
Hi Ken,
you might try:
SELECT s.PROJID,s.PROJECTNAME
FROM S_PROJECTREGISTER s
INNER JOIN SL_PROGPROJ l ON s.PROJID = l.PROJID AND l.SNAPSHOTID = 56
INNER JOIN SL_PORTPROG p ON l.PROGID = p.PROGID AND p.SNAPSHOTID = 56
AND p.PORTID IN (100994,100996)
WHERE s.SNAPSHOTID = 56
AND
Hi John,
I think you missed on the precedence of AND/OR
if you change to
AND (cat_id='2' OR cat_id='5' )
it should work as you want it to
/Johan
John Croson wrote:
I have a simple query:
SELECT id,year,month,day,cat_id FROM events
LEFT JOIN calendar_cat ON
events.cat=calendar_cat.cat_id
WHERE
Hi Doug,
I think you need to quote imgsml=C2BUWS1028.jpg, like
imgsml='C2BUWS1028.jpg',
take care,
/Johan
[EMAIL PROTECTED] wrote:
This has to be something silly, but I can not see it. Any help greatly
appreciated:
use newshop;
insert into products set storeid=2, deptid=5, groupid=66,
18 matches
Mail list logo