Please consider the following two tables:
mysql select * from os_table;
+---+--+
| os_id | os_name |
+---+--+
| 1 | mac os |
| 2 | win 95 |
| 4 | win 98 |
| 8 | win nt |
|16 | win 2000 |
|32 | win me |
|64 | xp home |
| 128 | xp
solutions
- where os.os_id = solutions.os_code
- and os.os_id = 8;
-ms
-Original Message-
From: John Hoskins [mailto:[EMAIL PROTECTED]
Sent: Wednesday, April 02, 2003 10:41 AM
To: [EMAIL PROTECTED]
Subject: select help
Please consider the following two tables
: Michael Shulman [mailto:[EMAIL PROTECTED]
Sent: Wednesday, April 02, 2003 11:38 AM
To: 'John Hoskins'
Cc: '[EMAIL PROTECTED]'
Subject: RE: select help
No problem. Use mod(m,n). To get the records where the 8 bit is set, use
and mod(os.os_id,8) = 0;
mysql use test
Database changed
mysql
Probably a simple query but, I need to find select a field with data that
exists in one table but does not exist in a field in another table.
example:
table1.name table2.name
---
bob john
susan
