where
b.lieferant is null
-Ursprüngliche Nachricht-
Von: Carlos Proal [mailto:carlos.pr...@gmail.com]
Bereitgestellt: Dienstag, 19. Jänner 2010 20:15
Bereitgestellt in: gmane.comp.db.mysql.general
Unterhaltung: Quick help with Insert
Betreff: Re: Quick help with Insert
Hi
Hey
Not really quick ; - But nobody knows an answer?
THX
-Ursprüngliche Nachricht-
Von: Intell! Soft [mailto:intellis...@fachoptiker.net]
Bereitgestellt: Donnerstag, 14. Jänner 2010 17:40
Bereitgestellt in: gmane.comp.db.mysql.general
Unterhaltung: Quick help with Insert
Betreff
an answer?
THX
-Ursprüngliche Nachricht-
Von: Intell! Soft [mailto:intellis...@fachoptiker.net]
Bereitgestellt: Donnerstag, 14. Jänner 2010 17:40
Bereitgestellt in: gmane.comp.db.mysql.general
Unterhaltung: Quick help with Insert
Betreff: Quick help with Insert
Hey
I would need quick help
...@gmail.com]
Bereitgestellt: Dienstag, 19. Jänner 2010 20:15
Bereitgestellt in: gmane.comp.db.mysql.general
Unterhaltung: Quick help with Insert
Betreff: Re: Quick help with Insert
Hi !!
You need a left join and then an insert.
Please read: http://dev.mysql.com/doc/refman/5.1/en/join.html or google
harsh [EMAIL PROTECTED] wrote:
Two databases
data1
data2
data1 has table1 and data2 has table2
both the tables have uid field common
I want to list out common uid's from table1 annd table2
Tried many commands as i understood from documentations
but somewhere i m always wrong.
Two databases
data1
data2
data1 has table1 and data2 has table2
both the tables have uid field common
I want to list out common uid's from table1 annd table2
Tried many commands as i understood from documentations
but somewhere i m always wrong.
thanks
regards
Corey Kaye writes:
Looking though the docs. MySQL does not support nested selects but i'm looking for a
way to speed up my PHP.
This is what i have:
CREATE TABLE departmentuser (
userid int(10) unsigned zerofill default NULL,
departmentid int(10) unsigned zerofill default NULL,
I looked that up and IN is an OR ... correct ?
Would be like saying:
Show me the records where departmentid = 142 OR departmentid = 368
I did however find this:
select * from departmentuser r1, departmentuser r2 where
r1.userid=r2.userid and r1.departmentid=368 and r2.departmentid=142;