Re: Adding a user problem

2003-01-27 Thread Doug Thompson
Assuming you logging in from the same server on which mysqld is running, you need a dmiller@localhost user. The "%" wildcard is valid only for tcp connections. This is thoroughly explained in the MySQL manual, chapter 4.3.5. hth, Doug On Mon, 27 Jan 2003 15:03:35 -0500, Devin Miller wrote: >I

Re: Adding a user problem

2003-01-27 Thread Mark
- Original Message - From: "Devin Miller" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Monday, January 27, 2003 9:03 PM Subject: Adding a user problem > I am pretty new to mysql and have been teaching myself slowly how > to use it. I am however stuck on

Re: Adding a user problem

2003-01-27 Thread Stefan Hinz, iConnect \(Berlin\)
mysql/bychapter/manual_MySQL_Database _Administration.html#Connection_access Regards, -- Stefan Hinz <[EMAIL PROTECTED]> Geschäftsführer / CEO iConnect GmbH <http://iConnect.de> Heesestr. 6, 12169 Berlin (Germany) Tel: +49 30 7970948-0 Fax: +49 30 7970948-3 - Original Message

Re: Adding a user problem

2003-01-27 Thread Thomas Kvamme
Devin Miller wrote: > > I am pretty new to mysql and have been teaching myself slowly how to use it. > I am however stuck on a problem. I login to mysql as user root and created a > database named devin. I then issue the following commands: > > GRANT ALL PRIVILEGES > ON devin.* > TO dmiller@"%" > I

Re: Adding a user problem

2003-01-27 Thread Paul DuBois
At 15:03 -0500 1/27/03, Devin Miller wrote: I am pretty new to mysql and have been teaching myself slowly how to use it. I am however stuck on a problem. I login to mysql as user root and created a database named devin. I then issue the following commands: GRANT ALL PRIVILEGES ON devin.* TO dmill

Adding a user problem

2003-01-27 Thread Devin Miller
I am pretty new to mysql and have been teaching myself slowly how to use it. I am however stuck on a problem. I login to mysql as user root and created a database named devin. I then issue the following commands: GRANT ALL PRIVILEGES ON devin.* TO dmiller@"%" IDENTIFIED BY "password"; The command