GROUP BY from_user_id;
In your original query I think you meant to select from, not to, since to will
be 1;
- Original Message -
From: "John Kopanas" <[EMAIL PROTECTED]>
To:
Sent: Sunday, March 11, 2007 12:59 PM
Subject: Re: Finding a Solution To A Distinct Problem of Mi
be 1;
- Original Message -
From: "John Kopanas" <[EMAIL PROTECTED]>
To:
Sent: Sunday, March 11, 2007 12:59 PM
Subject: Re: Finding a Solution To A Distinct Problem of Mine
I think I got it:
SELECT * FROM (SELECT * FROM messages ORDER BY created_at DESC) as
messages
Ok, did not work... hmmm... any other suggestions?
On 3/11/07, John Kopanas <[EMAIL PROTECTED]> wrote:
I think I got it:
SELECT * FROM (SELECT * FROM messages ORDER BY created_at DESC) as
messages WHERE to_user_id = 1 GROUP BY from_user_id;
Is this the best way about it... or are their better
I think I got it:
SELECT * FROM (SELECT * FROM messages ORDER BY created_at DESC) as
messages WHERE to_user_id = 1 GROUP BY from_user_id;
Is this the best way about it... or are their better ways you suggest?
On 3/11/07, John Kopanas <[EMAIL PROTECTED]> wrote:
I have the following table:
mess
I have the following table:
messages:
if:
from_user_id:
to_user_id:
body:
created_at:
updated_at:
I have to return all the rows that have a distinct from_user_id based
on a to_user_id. Not only that but I want to return the rows with the
newest created_at.
I thought this would work:
SELE
