On Apr 5, 2005 3:15 PM, Martijn Tonies <[EMAIL PROTECTED]> wrote: > Hi, > > > I'm designing a database for our new Application and have some > > problems with the following: > > > > We have a table Jobs in which we store all kind of Jobs. > > Looks like this: > > > > tbl_jobs > > ------------- > > job_id, integer, > > name, varchar, > > description, varchar > > > > easy so far :) > > The problem is we also want to keep track which of the Jobs are > > related or almost the same. > > > > Example: > > If we have the following jobs: > > 1 painter > > 2 auxiliary worker painter > > 3 plasterer > > 4 auxiliary worker plasterer > > 5 electrician > > 6 auxiliary worker electrician > > > > There will be 2 logical "groups": > > first: > > 1, 2, 3, 4 > > second: > > 5, 6 > > > > If I query for "plasterer" I should get the following result: > > - plasterer > > - painter > > - auxiliary worker painter > > - auxiliary worker plasterer > > > > If I query for "auxiliary worker electrician" I should get this: > > - electrician > > - auxiliary worker electrician > > > > What is the easiest way to design this? > > I thought about this the whole morning but couldn't get a solution. > > > > I hope somebody on this list can point me in the right direction. > > Well, you could add the concept of "job_group". Eg, create a table: > > job_groups > jg_id, integer > description varchar > > Add a group: > 1, electrician > 2, plasterer > > Now, if any job can belong to a single group, add a column "job_group" > to your jobs table. > > When finding results for a certain job, you can check it's job_group > and select any jobs from that group as well. > > With regards, > > Martijn Tonies > Database Workbench - developer tool for InterBase, Firebird, MySQL & MS SQL > Server > Upscene Productions > http://www.upscene.com > > -- > MySQL General Mailing List > For list archives: http://lists.mysql.com/mysql > To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] >
Thanks for your reply. I see this could be a possible solution. But isn't it possible to solve this problem somehow without having to create an additional job_group table? Regards, Olivier -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
