Many thanks for your kind response. I was using a form that was submitted twice
for any given new ssn. I have also benefited from your comments on how to write
a better java code. Turns out my html and javascript skills need improvement.
Many thanks again.
Regards
David Griffiths <[EMAIL P
This is a little dangerous as well; if an exception gets thrown, the
statement doesn't get closed. My sample code is below.
That said, your query looks fine. Add logging to your code to figure out
what's going on. Run your query by hand against your database; I suspect
you have an issue with
I tried everything you suggested. 'Think it is the way I have set up
the table in MYSQL. This is the table
++---+--+-+-+---+
| Field | Type | Null | Key | Default | Extra |
++---+--+-+-+---
Here is the code:
ps = con.prepareStatement("select first, last from cust where ssn=?");
int ssnint = Integer.parseInt(ssn.trim());
ps.setInt(1, ssnint);
ResultSet rs=ps.executeQuery();
if ( rs.next()) {
rs.close();
out.println("Cust
I am getting the same result in Java code, i.e. the resultset returned is
non-null even though the primary key value is not found in the table.
Hassan Schroeder <[EMAIL PROTECTED]> wrote: On 12/29/06, murthy gandikota
wrote:
> I am posting the relevant JSTL code.
Just to clarify: you're *not
Hi
I have created a table with the following specs:
create table `cust` (
`ssn` int(9) NOT NULL PRIMARY KEY,
`submitdate` date,
`submitto` int(3),
`first` varchar(30),
`last` varchar(30),
`loanAmt` decimal(10,2),
`company` int(3),
