Friday, August 18, 2006 12:37 PM
To: Robert DiFalco; 'mysql@lists.mysql.com'
Subject: RE: More query help for user-defined values
No takers?
-Original Message-
From: Robert DiFalco
Sent: Thursday, August 17, 2006 3:03 PM
To: Robert DiFalco; mysql@lists.mysql.com
Subject: RE: More query
No takers?
-Original Message-
From: Robert DiFalco
Sent: Thursday, August 17, 2006 3:03 PM
To: Robert DiFalco; mysql@lists.mysql.com
Subject: RE: More query help for user-defined values
One simple solution is to denormalize a little and take the refTypeID
column out of StringValue and
LL AND ST1.defaultVal LIKE 'foo' ) )
AND
( SV2.f_val LIKE 'bar' OR
( SV2.val IS NULL AND ST2.defaultVal LIKE 'bar' ) )
-Original Message-
From: Robert DiFalco [mailto:[EMAIL PROTECTED]
Sent: Thursday, August 17, 2006 8:43 AM
To: m
To support user defined properties I have the following tables:
TABLE StringType
LONG ID PKEY
VARCHAR name
...
VARCHAR defaultValue
TABLE StringValue
LONG parentID
LONG typeID
VARCHAR val
Assume the correct indices are in place. Different string value types
ca
Hi.
On Wed 2002-06-05 at 13:37:22 -0500, [EMAIL PROTECTED] wrote:
[...]
> It selects a list of all members from the database referred by a certain
> member. However, the query needs to be modified to also select the
> number of people that person has referred. I planned to just send
> another que
I probably did not provide enough info the first time. The members table
is setup as follows:
Id (primary key)
Referer (relates to the primary key of the table)
I am given a member ID, say 4. I need to display all members who have
been referred by member 4 (obviously no problem). However, for ea
First off, I would like to thank everyone on this lists who helps people
like myself!
I'm having trouble with the following query:
SELECT username, first_name, email, DATE_FORMAT(signup_date, '%b %e,
%Y') AS signup_date FROM members WHERE referer = (id)
It selects a list of all members from the
