well - that was what I tried first - but that does not work because that
returns the latest date for which the task_id has a record as Assignment.
(It is like it picks up the max date from all records that have
name_rec_type as Assignment)
But I wanted was if the date corresponding to the name_
Hi,
Try just :
SELECT id_secr_rqst task_id, MAX(dt_aud_rec) AS latest
FROM isr2_aud_log WHERE
name_rec_type = 'Assignment' AND id_secr_rqst
='TASK23C6054B9D416C08:1284FD4:103FB047DF1:-7ECF'
GROUP BY id_secr_rqst
;
++-+
| task_id
SOLVED:
I changed my query to include max(t1.dt_aud_rec) instead of t1.dt_aud_rec.
I had guessed that it required just a tweak here and there...
Does anybody have any other suggestions apart from this??
Thanks,
Anoop
On 6/2/05, Anoop kumar V <[EMAIL PROTECTED]> wrote:
>
> OK - I have found th
OK - I have found the cause of the inconsistency -
Whenever I have more than one record which has name_rec_type as 'Assignment'
I do not get any results (I get an empty result)
But if I have only one Assignment record then it returns the correct row.
Question is: How can I overcome this - I jus
Hi mysql-ers,
I need help in a basic query:
I have this table:
select * from isr2_aud_log where
id_secr_rqst IN ('TASK23C6054B9D416C08:1284FD4:103FB047DF1:-7ECF')
--and name_rec_type = 'Assignment'
order by id_secr_rqst, dt_aud_rec
++--
