Another PHP problem has kept me up all night, scouring through my database
books and trying everything I could think of. I am still new to the MySQL
and PHP field, but never the lass I will not give up.
$cat is a variable that is passed to the query from the previous page. The
SELECT statement
Another PHP problem has kept me up all night, scouring through my database
books and trying everything I could think of. I am still new to the MySQL
and PHP field, but never the lass I will not give up.
$cat is a variable that is passed to the query from the previous page. The
SELECT statement
Another PHP problem has kept me up all night, scouring through my database
books and trying everything I could think of. I am still new to the MySQL
and PHP field, but never the lass I will not give up.
$cat is a variable that is passed to the query from the previous page. The
SELECT statement
This really isn't a MySQL question and should be handled by another
list, But to answer your question (logically). You need to have the
whole string `productcategory.ID=\$cat\' optional, so that if your
variable `$cat' isn't populated the string
`productcategory.ID=\$cat\'
isn't included, Also
Neil,
Please indicate what you mean by converting the string x to a percent
value???
-Jason Garber
www.deltacron.com
At 08:51 AM 9/21/2001 +1000, Neil Silvester wrote:
Another PHP problem has kept me up all night, scouring through my database
books and trying everything I could think of. I