Thx's Fred...
as soon as I sent the email and re-read it again... I spotted the 'as' alias
table reference to the table, was actual a reserved word,..causing the error :)
thx's again.
--
MikeBlezien
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
Thunder Rain Internet Publishing
Providing Internet Solu
Mike Blezien said:
>
> I've been looking at this SQL query a dozen times or more, but keep
> getting a syntax error message, Query:
>
> SELECT ai.affilid,ai.create_date,CONCAT(ai.fname,' ',ai.lname) AS
> name,aw.siteid,ai.email,as.username,as.status
> FROM affiliate_info ai,affiliate_signup as,aff
On Tue, Jan 20, 2004 at 04:10:44PM -0600, Mike Blezien wrote:
> I've been looking at this SQL query a dozen times or more, but keep getting
> a syntax error message, Query:
>
> SELECT ai.affilid,ai.create_date,CONCAT(ai.fname,' ',ai.lname) AS
> name,aw.siteid,ai.email,as.username,as.status
> FRO
Hello all,
I've been looking at this SQL query a dozen times or more, but keep getting a
syntax error message, Query:
SELECT ai.affilid,ai.create_date,CONCAT(ai.fname,' ',ai.lname) AS
name,aw.siteid,ai.email,as.username,as.status
FROM affiliate_info ai,affiliate_signup as,affiliate_website aw
W
Dan,
SELECT ResourceTable.* FROM ResourceTable
LEFT JOIN ResourceLinkTable
ON ResourceTable.ResourceID = ResourceLinkTable.ResourceID
WHERE ResourceLinkTable.ResourceID IS NULL;
Regards,
Thomas
On Thu, 30 Oct 2003, Dan Lamb wrote:
> Hello All,
>
> I have two table the look like thi
Adam
-Original Message-
From: Dan Lamb [mailto:[EMAIL PROTECTED]
Sent: Thursday, October 30, 2003 9:39 AM
To: [EMAIL PROTECTED]
Subject: select query syntax help
Hello All,
I have two table the look like this (greatly simplified):
ResourceTable
-
int ResourceID
var Resourc
Hello All,
I have two table the look like this (greatly simplified):
ResourceTable
-
int ResourceID
var ResourceName
ResourceLinkTable
-
int ResourceLinkID
int ResourceID
var Text
I need to find all rows in ResourceTable for which there is NO entry in
ResourceLin
BY F.saveorder (another column) in
this case, unless you include it (F.saveorder) in the SELECT and GROUP BY
list.
HTH,
Tore.
- Original Message -
From: "Scott Brown" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Saturday, February 22, 2003 1:57 PM
Subject: Query s
OK, I am having a bit of trouble designing a MySQL query that returns what
I want. Here is the query as I have it thus far:
SELECT DISTINCT regformfields.name AS thename,
regformfields.label AS thelabel,
regfields.name AS fieldsname
FROM regformfie
dget)
Subject: Query syntax help
I'm trying to figure out a query that will tell me the total number of
people in our house email file that physically opted out in the last
week. I'm a bit of a mysql newbie as you can tell...
This is the general concept, though it doesn't seem to
> I'm trying to figure out a query that will tell me the total number of
> people in our house email file that physically opted out in the last
> week. I'm a bit of a mysql newbie as you can tell...
>
> This is the general concept, though it doesn't seem to work:
>
> select count(id) from conta
AND date >= "2002-03-17";
-Original Message-
From: rory oconnor [mailto:[EMAIL PROTECTED]]
Sent: Thursday, March 21, 2002 10:49 AM
To: mysql "list (choose midget)
Subject: Query syntax help
I'm trying to figure out a query that will tell me the total number of
pe
I'm trying to figure out a query that will tell me the total number of
people in our house email file that physically opted out in the last
week. I'm a bit of a mysql newbie as you can tell...
This is the general concept, though it doesn't seem to work:
select count(id) from contact # my
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