RE: Help with SELECT, JOIN and WHERE query

2003-01-29 Thread heiko mundle
: Re: Help with SELECT, JOIN and WHERE query From: Stefan Hinz, iConnect \(Berlin\) Date: Wed, 29 Jan 2003 00:02:22 +0100 Victor, good shot! I thought of this one in the first place: SELECT u.user_id FROM user_profile u LEFT JOIN team_member t ON u.user_id = t.user_id WHERE t.team_id 2

Re: Help with SELECT, JOIN and WHERE query

2003-01-28 Thread Dobromir Velev
Hi, a query like this should do the job select user_profile.user_id from user_profile left join team_member on (team_member.user_id=user_profile.user.id and team_member.team_id=2) where team_member.user_id is NULL; Dobromir Velev [EMAIL PROTECTED] www.websitepulse.com - Original Message

RE: Help with SELECT, JOIN and WHERE query

2003-01-28 Thread Victor Pendleton
SELECT u.user_id FROM user_profile u LEFT JOIN team_member t ON u.user_id = t.user_id WHERE t.team_id 2 -Original Message- From: heiko mundle [mailto:[EMAIL PROTECTED]] Sent: Tuesday, January 28, 2003 8:08 AM To: [EMAIL PROTECTED] Subject: Help with SELECT, JOIN and WHERE query Hi, I

Re: Help with SELECT, JOIN and WHERE query

2003-01-28 Thread William R. Mussatto
Hi, I got a difficult problem with a SELECT query: In my application there are two tables, one for all users (user_profile) one for a user-in-team relation. I want to know, which user is still not in a speciffic team. Users can be in more than one team, but we don't care about that. What

Re: Help with SELECT, JOIN and WHERE query

2003-01-28 Thread gerald_clark
WHERE team_member.user_id IS NULL William R. Mussatto wrote: Hi, I got a difficult problem with a SELECT query: In my application there are two tables, one for all users (user_profile) one for a user-in-team relation. I want to know, which user is still not in a speciffic team. Users can

Re: Help with SELECT, JOIN and WHERE query

2003-01-28 Thread Stefan Hinz, iConnect \(Berlin\)
Subject: RE: Help with SELECT, JOIN and WHERE query SELECT u.user_id FROM user_profile u LEFT JOIN team_member t ON u.user_id = t.user_id WHERE t.team_id 2 -Original Message- From: heiko mundle [mailto:[EMAIL PROTECTED]] Sent: Tuesday, January 28, 2003 8:08 AM To: [EMAIL PROTECTED] Subject