Hi Chris,
Chris W wrote:
I have 2 queries to give me a list of names.
Q1:
SELECT DISTINCT FName, LName
FROM user u
JOIN userprofile p
USING ( UserID )
JOIN trainingstatus t
USING ( UserID )
WHERE ProgramID =12
ORDER BY LName, FName
Q2
SELECT DISTINCT FName, LName
FROM namelist
WHERE `Date`
Wh
Shawn,
I've just found out that most of my emails during this discussion were
NOT posted to the list because I was sending mail in HTML format and
Yahoo was not delivering the bounce notices to me. That explains why you
believed I was not listening to Peter's input - only _his_ messages were
You are correct, that the situation you describe was not clearly presented
in your previous reply. I humbly apologize for any offense.
Using the EXPLAIN you posted in your latest reply, you can translate your
subquery into the following JOINed query
SELECT p.offer_id
FROM paytable p
LEFT JOIN
[EMAIL PROTECTED] wrote:
Devananda,
I have to support Peter on this one. What he submitted to you is a
perfectly appropriate solution. It seems as though you rejected his
assistance before even trying to see if it would work.
On the contrary, I have tried his suggestions and they do not work
Devananda,
I have to support Peter on this one. What he submitted to you is a
perfectly appropriate solution. It seems as though you rejected his
assistance before even trying to see if it would work. There have been and
continue to be SQL-driven databases around that have not had and do not
Devananda,
>Definitely not. The first LEFT JOIN, with the clauses
>"ON
pt.login_id=pab1.login_id ... WHERE pab1.login_id IS NULL",
> does not
make sense.
?!? It's a standard JOIN replacement for NOT IN (...).
>There is not a 1to1 relationship,
These joins neither find nor assume 1:1 rela
Devananda,
OK, get the diescription in ordinary language right, and the query
ought to write itself. Your schema is like this? ...
and you want the paytable rows
(i) for which there is an offers row matching paytable.offer_id, and
(ii) for which there is no pab row where
pab.login_
Devananda,
>Could anyone give me some insight as to which of the following
queries
>is "better" (and why) - or if there is another query that would be
faster than either?
It's late on Friday so I could be missing something, but wouldn't the
following be simpler?
SELECT offer_id
FROM paytab
> Select * from employees left outer join dept on employees.emp_DepId =
> dept.dep_id where dept.dep_id is null
>
> (Subselect would be easier if MySQL supported it!)
Likely easier to write, but equally likely to be more expensive to run
(on any tbl of realistic size)
NB Comment only pertinent a
Select * from employees left outer join dept on employees.emp_DepId =
dept.dep_id where dept.dep_id is null
(Subselect would be easier if MySQL supported it!)
HTH,
=C=
*
* Cal Evans
* The Virtual CIO
* http://www.calevans.com
*
-Original Message-
From: Silmara [mailto:[EMAIL PROTECTED]]
select a.* from a left join b on a.id = b.id
where b.id is null;
Ken Kinder wrote:
>
> Is there a way I can filter OUT records referenced in another table?
>
> With Subselects it would be this, but I'm using 3.23:
>
> select
> a.*
> from
> a
> where
> a.id not in (select id from b)
>
gt; mysql>
>
>
>
> - Original Message -
> From: "Kevin Smith" <[EMAIL PROTECTED]>
> To: "Mohamed Abd El-Samei Mohamed" <[EMAIL PROTECTED]>
> Sent: Thursday, December 13, 2001 2:25 PM
> Subject: Re: Not In
>
>
> > Post the
> Dear all can anyone help me to use NOT IN
>
> or NOT EXISTS command in mysql ..
You need to use left join the table and look for an inexisting link
select * from table 1
left join table2 on table2.key1=table1.id
where whatever
and table2.id is null
-
> Dear all can anyone help me to use NOT IN
>
> or NOT EXISTS command in mysql ..
You need to use left join the table and look for an inexisting link
select * from table 1
left join table2 on table2.key1=table1.id
where whatever
and table2.id is null
-
* Mohamed Abd El-Samei Mohamed
> Dear all can anyone help me to use NOT IN
>
> or NOT EXISTS command in mysql ..
None of these are commands...
NOT IN was introduced in version 3.21.14a, it is a variant of the IN
comparison operator. From the manual:
`expr NOT IN (value,...)'
Same as `NO
CREATE TABLE IF NOT EXISTS table_name (
id NOT NULL AUTO_INCREMENT PRIMARY KEY,
value VARCHAR(30) );
Mohamed Abd El-Samei Mohamed wrote:
MAEM: Date: Thu, 13 Dec 2001 13:59:46 +0200
MAEM: From: Mohamed Abd El-Samei Mohamed <[EMAIL PROTECTED]>
MAEM: To: [EMAIL PROTEC
At 4:40 PM -0700 9/7/01, Anthony E. wrote:
>I've tried to do a NOT IN statement, but still am
>getting SQL syntax error.
>
>
>SELECT COUNT(*) FROM USER_TMP WHERE USER_TMP.email NOT
>IN (SELECT USER.email FROM USER);
>
>I'm trying to produce a list of records from USER_TMP
Huh? COUNT(*) produces
o: "Beatriz Lapaz" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Monday, July 16, 2001 10:57 AM
Subject: Re: NOT IN
>
> here the script in php in eine classe eingebaut.
>
-
Before posting, plea
At 09:31 16.07.01 +0200, Beatriz Lapaz wrote:
>Hi!!
>
>I'm working with PHP and I use MySQL. I've just known that in MySQL
>doesn't exist NESTED SELECTS and it's a problem for me.
>I'd need a query to get all the ids from a table which are not in another
>table. Something like that:
>
>SELECT TA
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