-Original Message-
From: Chris Mason [mailto:masonc;masonc.com]
[...]
The problem is, it is easy to test for one amenity, but I need to test
that the hotel has all of the amenities. The query above
returns all the
hotels that have ANY of the amenities, I need the hotels having ALL
If you know the total number of amenities, n, then you could try this:
SELECT h.ID, count(*) as total
FROM AmenityLink al, Hotels h
where al.HotelID=h.ID
AND ShowHotel = 1
AND PostCode = '$postcode'
group by h.ID
having total=n
Hope it helps.
Cheers,
Clemente Zamora
GlobalReservas
