this means that the select-statement did not return a row.
try printing out the select-statement and execute it on the
command-line.
and add a "if ($result) {..." before using the result set.

and: try finding a php-list. :-)

> -----Original Message-----
> From: Alia Mikati [mailto:[EMAIL PROTECTED]]
> Sent: Friday, April 12, 2002 3:13 PM
> To: [EMAIL PROTECTED]
> Subject: functions in mysql again
> 
> 
> Hi again
> I'm getting this message now:
> Supplied argument is not a valid MySQL result resource ..at the 4th line. 
> What could be the problem now?
> Thx again
> 
> function AddItem($OrderID,$ProductID,$Qty)
> {
> $Datasource = new Datasource;
> $result = mysql_query("Select Count(*) FROM orderitemdetail WHERE    
> Product_Id=$ProductID AND Order_Id=$OrderID");
> $row = mysql_fetch_row($result); 
>                 
> if ($row[0]>0)              
> {
>  $SQL1 = "UPDATE orderitemdetail SET Quantity=Quantity+$Qty ". 
>        " WHERE Product_Id=$ProductID AND Order_Id=$OrderID";
> }
> else
> {
>  $SQL1 = "INSERT INTO orderitemdetail (Order_Id, Product_Id, Quantity)".
>          "VALUES($OrderID,$ProductID,1)";
> }
> $QueryResult = $Datasource->QueryDatasource($SQL1);
> return $QueryResult;}
> }
> 
> 
> 
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