Re: PHP Prob contd.

2001-06-10 Thread Whit Blauvelt
On Sun, Jun 10, 2001 at 08:18:08PM -0700, Vladimir Kravtsov wrote: > Well I fixed that part so now the file looks like this: > $sql = "select id, siteurl, sitename, from sitesats where validated = '$validated'"; > Warning: Supplied argument is not a valid MySQL result resource in >c:\inetpub\ww

Re: PHP Prob contd.

2001-06-10 Thread Rolf Hopkins
You have 1 too many commas. Remove the comma before the from clause in your sql statement. - Original Message - From: "Vladimir Kravtsov" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Monday, June 11, 2001 11:18 Subject: PHP Prob contd. Well I fixed that part so now the file looks