Re: counting question

2005-08-01 Thread Gleb Paharenko
Hello. What do you think about this: SELECT u.name, IFNULL(s.skill_name,'user doesn\'t have any skill') AS SKILL, ( SELECT COUNT(skill_id)

Re: counting question

2005-08-01 Thread Dean Karres
Thanks to all that responded about my counting question. Gleb Paharenko's solution using the sub-select and the LEFT JOINS was the closest to what I needed. All the best, Dean...K... -- Dean Karres / karres at itg dot uiuc dot edu / www.itg.uiuc.edu Imaging

Re: counting question

2005-07-31 Thread Parag Agrawal
Try this out: select user.name, skill.skill_name, count(user_skill1.skill_id) from user , skill, user_skill , user_skill as user_skill1 where user.id=user_skill.user_id and user_skill.skill_id=skill.id and skill.id = user_skill1.skill_id order by user.id. I think this would work. -- Parag

Re: counting question

2005-07-31 Thread Enrique Sanchez Vela
I could not help to resist to create the tables and try the hint, which is pretty close to the working solution. I just had to replace order by user.id with group by user.name skill.skill_name regards, esv. --- Parag Agrawal [EMAIL PROTECTED] wrote: Try this out: select user.name,

RE: Counting question

2003-07-03 Thread Andy Eastham
Try this: select delivery, count(*) as ticketcount from ticketsales where delivery=post or delivery=pickup group by delivery Andy -Original Message- From: Ville Mattila [mailto:[EMAIL PROTECTED] Sent: 03 July 2003 11:28 To: [EMAIL PROTECTED] Subject: Counting question Hi there,