hi, Peter
Try this:
select a.name, sum(if (b.table_a.id is NULL,0,1)) as indid from table_a a
left join table_b b on(a.id=b.table_id.id) group by a.id;
best regards,
Leo Huang
2006/6/1, Peter Lauri [EMAIL PROTECTED]:
Hi,
I have a table table_a and table_b:
table_a {
id
name
}
table_b {
Solved it by:
SELECT table_a.name , if( table_a.id = table_b.table_a_id, 1, 0 ) AS
theindicator
FROM table_a
LEFT OUTER JOIN table_b ON ( table_a.id = table_b.table_a_id )
/Peter
Hi,
I have a table table_a and table_b:
table_a {
id
name
}
table_b {
table_a_id
b_value
}
Table
Hi,
I have a table table_a and table_b:
table_a {
id
name
}
table_b {
table_a_id
b_value
}
Table A is a table with names, and table B is a table with values for a
specific name (optional, therefore a specific table).
I would like to select all records in A, done by:
SELECT name FROM table_a;
