Yes, you are right. It's the json_encode that fail.
It's strange though. The data that fail is "Humlebæk".
Another query, in another form, returning "Værksted" don't
fail in json_encode.
echo $cust['oname'];give the correct value.
On Tue, September 22, 2009 22:56, Mark Goodge wrote:
> Mogen
Mogens Melander wrote:
Well, no typos.
The relevant piece of code:
if (! $cust = mysql_fetch_assoc($res))
{
echo "{success: false, errors: { reason: 'Fetch Customer failed: " .
htmlspecialchars(mysql_error(),ENT_QUOTES) .
"" . htmlspecialchars($sql,ENT_QU
t; You didn't show your php code, but I'd bet you have a typo, likely
>> in assigning the returned value to the variable, or in the name of
>> the variable you're printing.
>>
>> - Rick
>>
>>
>>
>> Original Message --
the returned value to the variable, or in the name of
> the variable you're printing.
>
> - Rick
>
>
>
> Original Message
>> Date: Tuesday, September 22, 2009 10:02:06 PM +0200
>> From: Mogens Melander
>> To: mysql@lists.m
Hi guys
I'm getting rather confused on this thing.
Results returned from mysql console/query-browser is
different from what's returned from same query in PHP.
Maybe someone smarter than me could shed some light on
what's going on. I'm clueless :(
Environment is as follow:
Mysql Server version:
