uot;;
> $query .= "ORDER BY Restaurant.Price ";
> $mysql_result=mysql_query($query, $db) OR DIE ("died at query");
>
> -code here-
>
>
> -Original Message-
> From: Rolf Hopkins [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, Febr
";
$query .= "FROM Restaurant ";
$query .= "WHERE '$CuisineTemp' = Restaurant.Cuisine AND '$AreaTemp' =
Restaurant.Area ";
$query .= "ORDER BY Restaurant.Price ";
$mysql_result=mysql_query($query, $db) OR DIE ("died at query");
---
nsman, Scott" <[EMAIL PROTECTED]>
To: "'Rolf Hopkins'" <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Wednesday, February 14, 2001 23:29
Subject: RE: mySQL/php query help
> hey rolf--
>
> everything works fine if the user chooses "ALL&quo
Original Message -
From: "Stinsman, Scott" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, February 13, 2001 23:17
Subject: mySQL/php query help
> can anyone figure out why the following code works fine when both select
> variables = "ALL" and also
PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, February 13, 2001 23:17
Subject: mySQL/php query help
> can anyone figure out why the following code works fine when both select
> variables = "ALL" and also when only 1 of the 2 ="ALL" but NOT when BOTH
> select var
can anyone figure out why the following code works fine when both select
variables = "ALL" and also when only 1 of the 2 ="ALL" but NOT when BOTH
select variables equal something other than "ALL"?
here is the code:
What area of the city would you like to dine in?
\n";
$select.="ALL\n";
w
