Hi!
On Jul 13, Alexander Newald wrote:
> Hello,
>
> I have a table with id (char(8)) and value (int(8))
>
> To make my problem clear:
>
> There is no set with id = "20030713"
> insert into table values ("20030713","10");
>
> The next set is ("20030713","20") but as a set with 20030713 is
> alr
On Sun, Jul 13, 2003 at 09:52:10AM -0400, Paul Chvostek wrote:
...
> $q = "UPDATE table SET value=value+$value WHERE id='$id';";
> $q .= "INSERT INTO table (id,value) VALUES ('$id',$value)";
> @mysql_query($q);
Woop, I forgot this was the mysql list, not a php- list. ;-)
The basic thing
On Sun, Jul 13, 2003 at 11:50:40AM +0200, Alexander Newald wrote:
>
> I'm looking for a solution to write a sql query that inserts a set of data if the
> data id is not present and otherwise update the set.
We covered some of this in a thread named "Bulk loading data" that
started on July 8th.
Try this:
set @w = 0;
select @w := value from table where id = "20030713";
delete from table where id = "20030713";
insert into table values ("20030713", @w + 20);
[EMAIL PROTECTED] wrote:
Hello,
I'm looking for a solution to write a sql query that inserts a set of data if the data id is not
Hello,
I'm looking for a solution to write a sql query that inserts a set of data if the data
id is not present and otherwise update the set.
I have a table with id (char(8)) and value (int(8))
To make my problem clear:
There is no set with id = "20030713"
insert into table values ("20030713",
