sangprabv wrote:
I have these query:
SELECT SUM(price)*0.5 AS price1 FROM table WHERE partner = 'A';
SELECT SUM(price)*0.65 AS price2 FROM table WHERE partner = 'B';
Is it possible to make the queries into 1 single query? How to make it
happen? Many thanks for helps.
Willy
You can
Many thanks for the query. It works ;)
Willy
On Fri, 2009-09-04 at 08:09 +0200, Wolfgang Schaefer wrote:
sangprabv wrote:
I have these query:
SELECT SUM(price)*0.5 AS price1 FROM table WHERE partner = 'A';
SELECT SUM(price)*0.65 AS price2 FROM table WHERE partner = 'B';
Is it
Many thanks for your query, seems we need to group it like Wolfgang's
does.
Willy
On Thu, 2009-09-03 at 22:33 -0700, Manasi Save wrote:
may be you can use IN clause:
SELECT SUM(price)*0.5 AS price1, SUM(price)*0.65 AS price2 FROM table
WHERE partner IN ('A', 'B');
--
MySQL General
I have these query:
SELECT SUM(price)*0.5 AS price1 FROM table WHERE partner = 'A';
SELECT SUM(price)*0.65 AS price2 FROM table WHERE partner = 'B';
Is it possible to make the queries into 1 single query? How to make it
happen? Many thanks for helps.
Willy
--
MySQL General Mailing List
For
It's not clear what exactly you are looking for. Two possible solutions:
1) use a union
2) use a join with another table containing partner and factor fields.
Can you give a short example of what the input looks like and what you
would like the output to look like?
Regards,
- Robert
On Thu,
What I'm looking for is to SUM the price from partner A and B with each
result. So the result I expect is like Partner A total's price 123,
Partner B total's price 456. Can you give me the query example? TIA.
Willy
On Thu, 2009-09-03 at 23:11 -0400, Robert Citek wrote:
It's not clear what
Because these are two quite distinct queries, I don't see an immediate way of
joining them that would make them more efficient. Something that comes to mind
are sub-select statements for example, but that would make this more complex
than it needs to be.
Like Robert said, you aren't giving us
may be you can use IN clause:
SELECT SUM(price)*0.5 AS price1, SUM(price)*0.65 AS price2 FROM table
WHERE partner IN ('A', 'B');
--
Thanks and Regards,
Manasi Save
Artificial Machines Pvt Ltd.
I have these query:
SELECT SUM(price)*0.5 AS price1 FROM table WHERE partner = 'A';
SELECT
