Assuming that you have nodes representing suit en value, all cards can be
created like this.
match (s:suit),(v:value)
with s,v
create (s)<-[:SUIT]-(c:CARD)-[:VALUE]->(v)
Best, Tom
On Friday, 2 May 2014 22:33:15 UTC+2, Gabriel Peschl wrote:
>
> Hi everyone,
>
> I would like know how I can perfor
Hi everyone,
I would like know how I can perform a cartesian product in 2 graph, stored
in neo4j.
For example:
the first graph I have this nodes:
Ace
King
Jack
in the second graph, I have this nodes:
Hearts
Diamonds
Clubs
So, the result after the cartesian product:
First node: (Ace, Hearts)
Salut
En fait je veux utiliser l'option merge de cypher
mais j'ai une problème
MERGE ( AdresseClient : Clients { name: splitArray[5] })
je sais que dois respecter le syntaxe et met splitArray[5] entre deux cotes
mais j'ai écrit un pg qui va parser une ligne en des champs et le
name doit prendre
Hey folks,
I am very new to neo4j. Can you please suggest the way how to
import the following data in to ne04j.
[0,0,[[1,1],[3,3]]]
[1,0,[[0,1],[2,2],[3,1]]]
[2,0,[[1,2],[4,4]]]
[3,0,[[0,3],[1,1],[4,4]]]
[4,0,[[3,4],[2,4]]]
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Understood, thanks :)
Michael
On Friday, May 2, 2014 4:17:35 PM UTC+2, Michael Hunger wrote:
>
> In the first case it adds the label to the node record and the node to the
> label-node-index which it then uses for search
>
> In the second case it searches all nodes with that label, has to load
For both there is a 2.0 branch
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Am 02.05.2014 um 14:18 schrieb "Davide D'Alto" :
> Thank you very much, I've missed the neo4j jdbc driver I'll take a look at it
>
>
> On Fri, May 2, 2014 at 1:16 PM, Alex Frieden wrote:
>> What version of neo4j are you running? In gener
In the first case it adds the label to the node record and the node to the
label-node-index which it then uses for search
In the second case it searches all nodes with that label, has to load their
properties and check the property for the value on each node
So in my experience the first approa
Look at the file size on disk
Propertystore, stringstore and arraystore
Michael
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Am 02.05.2014 um 15:28 schrieb Alex Frieden :
> Is there a way to check how big the neo4j propertystore is? Thanks!
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Is there a way to check how big the neo4j propertystore is? Thanks!
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For more option
Suppose a "Notification" entity.
To keep thing simple, let's assume a single property: "*readFlag*", that
could be *true* if the notification was already read by the client, or
*false* if it is new or not checked by the client yet.
What is the difference in term of performance between those both
We've been seeing similar (intermittent) errors for some time but as yet
have been unable to build a standalone piece of code that reliably
generates the error.
One workaround I have tried is to ensure all nodes and relationships in a
query have an explicit identifier, e.g. dummy1, dummy2 and so o
Thank you very much, I've missed the neo4j jdbc driver I'll take a look at
it
On Fri, May 2, 2014 at 1:16 PM, Alex Frieden wrote:
> What version of neo4j are you running? In general I would recommend using
> the neo4j jdbc driver
> On May 2, 2014 7:39 AM, "Davide D'Alto" wrote:
>
>> Hi,
>> I
What version of neo4j are you running? In general I would recommend using
the neo4j jdbc driver
On May 2, 2014 7:39 AM, "Davide D'Alto" wrote:
> Hi,
> I need a java client to connect to Neo4j and I've seen the java-rest-bind
> project on github.
> The project is still using neo4j version 1.9.x a
Hi,
I need a java client to connect to Neo4j and I've seen the java-rest-bind
project on github.
The project is still using neo4j version 1.9.x and I was wondering what the
state of it.
Thanks,
Davide
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Fulltrxt indexes are by default case insensitive
Otherwise you might want to use toupper or toLower on either side
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Am 01.05.2014 um 15:47 schrieb Mathieu Durand :
> Hi,
>
> Does anybody know how to perform case insensitive cypher queries with Spring
> Data Neo4j.
> I'm
Same results on community versions of 2.0.1 and 2.1.0-M01.
On Thursday, May 1, 2014 8:39:12 PM UTC+8, Michael Hunger wrote:
>
> Can you please share the versions you are using?
>
>
> Am 01.05.2014 um 11:03 schrieb Yu Gene Loh
> >:
>
> Some queries are returning intermittent InvalidSyntax (Unknow
It think there were some issues with the upgrade in m01, please try the upgrade
again with m02 or m03 and report back
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Am 01.05.2014 um 14:32 schrieb Koen Kleingeld :
> hi, i used the 2.0.0 batch importer from few months ago.. the datastore was
> automatically converted
Thanks! Michael, will try this out
On Thursday, May 1, 2014 5:15:12 PM UTC+8, Michael Hunger wrote:
>
> 1. Use labels + indexes (or constraints)
>
> Without an label + existing index your first operation (merge) will have
> to go over all nodes in the graph to find if there is already a duplicate
Thanks a lot. Good work looking forward to the finished work.
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Am 01.05.2014 um 20:23 schrieb b...@devel.io:
> Michael, I wrote up a quick blog post with an overview of the goals and
> current status: http://devel.io/2014/05/01/cypher-compiler-for-python/
> --
> You rece
Hi,
We delete the current relationship because we need to have one type of the
same relationship per node.
Mark
On Wednesday, April 30, 2014 7:12:36 PM UTC+8, Mark Needham wrote:
>
> Hi,
>
> Do you know how about 'sku' relationships you're trying to delete in one
> go?
>
> Mark
>
>
> On 30 Apr
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