so any solutions for this case, Lundin?
Please help.
Thank you.
On Saturday, April 5, 2014 7:41:51 PM UTC+7, Rio Eduardo wrote:
>
> I already tried like you did before you did it
> if (position.length()>2){position.length()>2}else{position.length()>1}
>
> and again it doesn't work because it alwa
I already tried like you did before you did it
if (position.length()>2){position.length()>2}else{position.length()>1}
and again it doesn't work because it always execute the else statement
position.length()>1
and if I set condition statement like this:
if (position.length()==2){position.length()>
What have you tried so far?
The filter body code is sent as javascript and interpreted on the server,
test the length before doing the filtering
if (position.length()>2){position.length()>2}else{position.length()>1}
would work in both cases.
Den lördagen den 5:e april 2014 kl. 06:23:59 UTC+2 s
yeah because if the model graph is changed, the way to return filter also
changes. For example:
In your case here:
CREATE (Pontus:People { name:'Pontus Lundin' }),(John:People { name: 'John
Hellberg' }),(Jack:People { name: 'Jack Hellberg' }),(Sandra:People { name:
'Sandra
Johansson', sex:'fema
What does
start n = node(1) match p=n-[*3]->(x) return x, length(p)
and
start n = node(1) match p=n-[*4]->(x) return x, length(p)
Yields ?
n lördagen den 5:e april 2014 kl. 02:37:58 UTC+2 skrev Rio Eduardo:
I'm sorry Lundin, I asked the wrong question. I meant how to check if there
> ar
First, why do you say it works sometimes ? That sounds like a bug to me in
that case. Can you please start with a small dataset so you know and being
sure that you know whats going on in the graph ?
CREATE (Pontus:People { name:'Pontus Lundin' }),(John:People { name: 'John
Hellberg' }),(Jack:Pe
I'm sorry Lundin, I asked the wrong question. I meant how to check if there
are only 3 depth level in graph?
On Saturday, April 5, 2014 7:25:48 AM UTC+7, Rio Eduardo wrote:
>
> Lundin, Do you know the way how to count many relationships in the graph
> because I don't see it in the doc(method for
Lundin, Do you know the way how to count many relationships in the graph
because I don't see it in the doc(method for the position object(the path))?
Thank you.
On Saturday, April 5, 2014 12:43:01 AM UTC+7, Lundin wrote:
>
> Have you tried experimenting with ther filter and the path length ?
> e
Thank you for the reply Lundin. I already tried it, but in some conditions
it doesn't work(it returns nodes that shouldn't be returned). That's why I
found out the other ways to make condition that can work in many conditions.
On Saturday, April 5, 2014 12:43:01 AM UTC+7, Lundin wrote:
>
> Have
Have you tried experimenting with ther filter and the path length ?
endNod() is not the only method for the position object(the path), Mabey
position.length>1 or something.
Den fredagen den 4:e april 2014 kl. 18:10:33 UTC+2 skrev Rio Eduardo:
>
> Please anyone in this group help me. I already pos
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