Depends on what you count If you count every co-occurence then the current approach is correct
But your idea is a good variant Von meinem iPhone gesendet > Am 16.02.2016 um 16:54 schrieb Hashim Sharif <hashim.shar...@gmail.com>: > > Hi All, > > I believe the Movie Graph tutorial needs a small update in the Recommended > screen where it is describing how to (Extend Tom Hanks co-actors, to find > co-co-actors who haven't work with Tom Hanks...). > The query resulted in Strength of 5 with Tom Cruise because Tom Hanks has 3 > movies with Meg Rayan , so actual strength with Tom Cruise should be only 3. > After modifying the query (change count(*) to count (DISTNICT (coActors) the > result will be the actual strength and the higher will be Cuba Gooding Jr. > and Zach Grenier with 4 > hope you liked this :) > Thanks for Reading > Regards, > Hashim > -- > You received this message because you are subscribed to the Google Groups > "Neo4j" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to neo4j+unsubscr...@googlegroups.com. > For more options, visit https://groups.google.com/d/optout. -- You received this message because you are subscribed to the Google Groups "Neo4j" group. To unsubscribe from this group and stop receiving emails from it, send an email to neo4j+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
