Re: [neonixie-l] ScopeClock with teensy4.0

2023-11-20 Thread GDR GDR
wow! while the technical details are all "greek" to me, the images look amazing. I love the "artifacts" in them. I dont know how you took these, but it looks awesome! I like it as it is! not sure how this looks like in "motion" but looks great in the stills... can you post some more? cheers On

Re: [neonixie-l] Karlsson KA2000 owners - help with power supply...

2023-11-18 Thread GDR GDR
Sat, 18 Nov 2023, 22:14 GDR GDR, wrote: > >> pardon my ignorance here, but would it be ok to plug this into a AC to AC >> adapter 9VAC output but with 1000mA ? meaning does the 300mA output matters >> or can I got higher? thank you! >> >> On Saturday, November 1

Re: [neonixie-l] Karlsson KA2000 owners - help with power supply...

2023-11-18 Thread GDR GDR
ity. The power supply is probably a > transformer-based power supply without a Gretzsch bridge. > > Adam > > sobota, 18 listopada 2023 o 21:16:06 UTC+1 David Pye napisał(a): > >> If it's ac it doesn't have a polarity per se. >> >> >> Da

Re: [neonixie-l] Karlsson KA2000 owners - help with power supply...

2023-11-18 Thread GDR GDR
da 2023 o 21:16:06 UTC+1 David Pye napisał(a): > >> If it's ac it doesn't have a polarity per se. >> >> >> David >> >> >> On Sat, 18 Nov 2023, 20:07 GDR GDR, wrote: >> >>> hi there. I recently acquired a Karlsson KA2000 nix

Re: [neonixie-l] Karlsson KA2000 owners - help with power supply...

2023-11-18 Thread GDR GDR
November 18, 2023 at 2:32:55 PM UTC-6 Robert wrote: > Here’s the original power supply form my Karlsson > > [image: image0.jpeg] > > > Rob > > On 18 Nov 2023, at 20:07, GDR GDR wrote: > > hi there. I recently acquired a Karlsson KA2000 nixies clock, but it >

[neonixie-l] Karlsson KA2000 owners - help with power supply...

2023-11-18 Thread GDR GDR
hi there. I recently acquired a Karlsson KA2000 nixies clock, but it didn't come with a power plug/supply. the clock label states 9VAC 300mA 50/60Hz, which tells me I can just get any power plug of 9V and min 300mA (correct me if I'm wrong), but the question is the polarity of the plug. hence,