+1 on "why are you doing this?". However, to answer the question - rather than spawning a new shell for every request, use a loop in your bash script that is driven by access log output.
For example. tail -n0 -f /var/log/nginx/access.log | \ while read; do echo "one request"; done; You'll need to handle what happens when log rotation takes place. On Fri, 18 Aug 2023 21:39:13 -0400 Jeff Dyke <jeff.d...@gmail.com> wrote: > Can you explain why? I would never tie a script to a request. I post > process logs all of the time. If it needs to be in the application, don't > force it into Nginx. > > Strong statement, but would love to hear why? > > On Fri, Aug 18, 2023 at 9:47 AM Kaushal Shriyan <kaushalshri...@gmail.com> > wrote: > > > Hi, > > > > I am running nginx version: nginx/1.24.0 on CentOS Linux release 7.9.2009 > > (Core) > > > > # nginx -v > > nginx version: nginx/1.24.0 > > # cat /etc/redhat-release > > CentOS Linux release 7.9.2009 (Core) > > # > > > > I want to run a shell script every time my nginx server receives any HTTP > > request. Any simple ways to do this? > > > > Please guide me. Thanks in Advance. > > > > Best Regards, > > > > Kaushal > > > > _______________________________________________ > > nginx mailing list > > nginx@nginx.org > > https://mailman.nginx.org/mailman/listinfo/nginx > > _______________________________________________ nginx mailing list nginx@nginx.org https://mailman.nginx.org/mailman/listinfo/nginx