Varargs forwarding.

2020-08-24 Thread jibal
Write a macro to generate a call to `echo`.

Varargs forwarding.

2020-08-24 Thread shirleyquirk
Yeah that's what @lscrd meant about having to loop through with `stdout.write`, if you want to duplicate `echo`'s behaviour proc p1(args: varargs[string, `$`]) = for a in args: stdout.write(a) stdout.write('\n') proc p2(args: varargs[string, `$`]) = p1(

Varargs forwarding.

2020-08-24 Thread alexeypetrushin
Seems like `unpack_varargs` behaves not exactly as calling directly import macros proc p(args: varargs[string, `$`]) = unpack_varargs(echo, args) p 1, 2, 3 echo 1, 2, 3 Run Produces ["1", "2", "3"] 123 Run

Varargs forwarding.

2020-08-24 Thread lscrd
I have never been able to make `varargs[typed, `$`]` work. I use `string` instead of `typed`: proc p(args: varargs[string, `$`]) = echo args Run Unfortunately, `args` is displayed as an array and you have to loop on the elements and use `stdout.write` to get wha

Varargs forwarding.

2020-08-24 Thread alexeypetrushin
I hit exactly the same case, when I wanted to write wrapper p for echo, can you guys please explain how to do that? 1) Why can't I use proc proc p*(args: varargs[typed, `$`]) = echo args Run 2) Do I have to use the template here? (It compiles but still not work)