print dates in reversed order

If you know the number of entries up front, you can also do something like this and pre-allocate the sequence: import times, algorithm const limit = 3 let today = now() var sq = newSeq[string](limit) for i in 1..3: var duration = initDuration(days = i)

print dates in reversed order

you can use countdown: import times, algorithm var today = now() var sq: seq[string] for i in countdown(3, 1): var duration = initDuration(days = i) var next_day = today + duration sq.add($next_day.format(", dd-MMM-")) for e in sq:

print dates in reversed order

If the dates in your seq are stored as "-MM-dd" you can sort them alphanumerically using `sort`. Then I converted them back to the format you used incase that is a requirement. import algorithm, sequtils, times var dates = @["2021-05-31", "1972-07-01", "2020-01-31", "19

print dates in reversed order

Using my chrono ( ) library and countdown you can go pretty short: import chrono, times for i in countdown(2, 0): var cal = Timestamp(epochTime()).calendar cal.add(Day, i) echo cal.format("{weekday}, {day/2}-{month/n/3}-{yea

print dates in reversed order

Not so much about idiomatic/shorter, but more for performance/efficiency. IIRC `reversed` returns a new seq and therefore requires allocation. Use `reverse` to do reversal in place. Or you can do a for loop on the index in decreasing order to avoid reverse altogether. Also, if you know the numb

print dates in reversed order

Any improvements, shorter, more idiomatic (golf?) Nim? import times, algorithm var today = now() var sq: seq[string] for i in 1..3: var duration = initDuration(days = i) var next_day = today + duration sq.add($next_day.format(", dd-MMM-"))