On Mon, Apr 29, 2019 at 9:00 PM Nitish Saboo <nitish.sabo...@gmail.com> wrote:
> I am new to Nan and I want to get rid of the following code snippet
>
> But before that I need to understand what exactly is being returned from this
> method.
>
> Local<Object> obj;
>
> NAN_METHOD(process) {
> if (info.Length() == 0 || !info[0]->IsObject()) {
> std::cerr << "Must pass event object as first argument" << std::endl;
> info.GetReturnValue().Set(Nan::Null());
> return;
> }
>
> auto req = info[0]->ToObject();
> auto program = Nan::Get(req,
> Nan::New<String>("program").ToLocalChecked()).ToLocalChecked();
> auto message = Nan::Get(req,
> Nan::New<String>("message").ToLocalChecked()).ToLocalChecked();
> if (!program->IsString() || !message->IsString()) {
> std::cerr << "Must provide program and message keys in event object" <<
> std::endl;
> info.GetReturnValue().Set(Nan::Null());
> return;
> }
>
>
> Nan::Utf8String app(Nan::To<String>(program).ToLocalChecked());
> Nan::Utf8String msg(Nan::To<String>(message).ToLocalChecked());
>
> obj = req;
> match(*msg, msg.length(), *app, app.length());
> info.GetReturnValue().Set(obj);
> }
> program and message both are strings.
>
> match is a C method that is being called with return type void.
>
> 1)What is info.GetReturnValue().Set(obj) doing? Is this making any changes to
> obj because of some manipulation in the match function?
It's not making changes to `obj` but it stores it in a slot on the
`info` object.
> 2)What is being returned from this method?
In C++? Nothing (i.e., void.)
The JS return value is stored out of line.
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