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On Tuesday, October 9, 2012 at 12:25 AM, greelgorke wrote:
why so complicated? just find out the url of the ajax request and do it
yourself with whatever lib you want
The request lib will automatically decompress the response for you. I think
you'd be better off using http.request or http.get directly and avoiding any
possible double handling. You can still pipe the response as you are now.
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