On Tue, 9 Oct 2018, Alan Braslau wrote:
On Mon, 8 Oct 2018 17:56:24 -0400 (EDT)
Aditya Mahajan wrote:
Here is a proof of concept implementation in Lua + MP so that you can use:
\ContourPlot
[
function=2*x^5 + x*y + y^5,
x={0, 2},
y={-2, 0.5},
n=1000, % Number of discre
On Mon, 8 Oct 2018 17:56:24 -0400 (EDT)
Aditya Mahajan wrote:
> Here is a proof of concept implementation in Lua + MP so that you can use:
>
> \ContourPlot
>[
> function=2*x^5 + x*y + y^5,
> x={0, 2},
> y={-2, 0.5},
> n=1000, % Number of discretization points
>]
>
>
Wow! This is cool!
I must admit I do not get how the connections between MetaPost and Lua
works, but it seem to work fine.
Challenge: To do this for a more complicated closed and self-intersecting
curve like the
Bernoulli lemniscate, say (x^2+y^2)^2=x^2-y^2 (a good domain could be
-1.5 wrote:
>
On 10/8/2018 11:25 PM, Aditya Mahajan wrote:
On Mon, 8 Oct 2018, Alan Braslau wrote:
On Mon, 8 Oct 2018 16:00:10 -0400 (EDT)
Aditya Mahajan wrote:
On Sun, 7 Oct 2018, Hans Hagen wrote:
On 10/7/2018 7:14 PM, Alan Braslau wrote:
On Sun, 7 Oct 2018 17:25:35 +0200
"Mikael P. Sundqvist" wrote
On Mon, 8 Oct 2018, Aditya Mahajan wrote:
On Mon, 8 Oct 2018, Alan Braslau wrote:
On Mon, 8 Oct 2018 16:00:10 -0400 (EDT)
Aditya Mahajan wrote:
On Sun, 7 Oct 2018, Hans Hagen wrote:
On 10/7/2018 7:14 PM, Alan Braslau wrote:
On Sun, 7 Oct 2018 17:25:35 +0200
"Mikael P. Sundqvist" wrote:
On Mon, 8 Oct 2018 17:25:24 -0400 (EDT)
Aditya Mahajan wrote:
> > (then eps should be made a linear function of xi)
>
> Oh, I missed that. Thanks.
This is because the function is O(xy) for small x so one will get oscillations
in the curve (multiple hits in the grid search) otherwise.
Alan
_
On Mon, 8 Oct 2018, Alan Braslau wrote:
On Mon, 8 Oct 2018 16:00:10 -0400 (EDT)
Aditya Mahajan wrote:
On Sun, 7 Oct 2018, Hans Hagen wrote:
On 10/7/2018 7:14 PM, Alan Braslau wrote:
On Sun, 7 Oct 2018 17:25:35 +0200
"Mikael P. Sundqvist" wrote:
ContourPlot[2 x^5 + x y + y^5 == 0, {x, 0,
On Mon, 8 Oct 2018 16:00:10 -0400 (EDT)
Aditya Mahajan wrote:
> On Sun, 7 Oct 2018, Hans Hagen wrote:
>
> > On 10/7/2018 7:14 PM, Alan Braslau wrote:
> >> On Sun, 7 Oct 2018 17:25:35 +0200
> >> "Mikael P. Sundqvist" wrote:
> >>
> >>> ContourPlot[2 x^5 + x y + y^5 == 0, {x, 0, 2}, {y, -2, 1
On Sun, 7 Oct 2018, Hans Hagen wrote:
On 10/7/2018 7:14 PM, Alan Braslau wrote:
On Sun, 7 Oct 2018 17:25:35 +0200
"Mikael P. Sundqvist" wrote:
ContourPlot[2 x^5 + x y + y^5 == 0, {x, 0, 2}, {y, -2, 1/2}]
Brut force:
[...]
as this takes some time here's a cheat:
\starttext
\startbuffer[
On 10/7/2018 7:14 PM, Alan Braslau wrote:
On Sun, 7 Oct 2018 17:25:35 +0200
"Mikael P. Sundqvist" wrote:
ContourPlot[2 x^5 + x y + y^5 == 0, {x, 0, 2}, {y, -2, 1/2}]
Brut force:
\startTEXpage
\startMPcode {doublefun}
pen savedpen ; savedpen := currentpen ;
pickup pencircle scaled .01 ;
path
On Sun, Oct 7, 2018 at 7:14 PM Alan Braslau wrote:
>
> On Sun, 7 Oct 2018 17:25:35 +0200
> "Mikael P. Sundqvist" wrote:
>
> > ContourPlot[2 x^5 + x y + y^5 == 0, {x, 0, 2}, {y, -2, 1/2}]
>
> Brut force:
>
> \startTEXpage
> \startMPcode {doublefun}
> pen savedpen ; savedpen := currentpen ;
> picku
On Sun, 7 Oct 2018 17:25:35 +0200
"Mikael P. Sundqvist" wrote:
> ContourPlot[2 x^5 + x y + y^5 == 0, {x, 0, 2}, {y, -2, 1/2}]
Brut force:
\startTEXpage
\startMPcode {doublefun}
pen savedpen ; savedpen := currentpen ;
pickup pencircle scaled .01 ;
path p ;
p := for i=0 upto 1000 :
for j=0
On Sun, Oct 7, 2018 at 5:26 PM Mikael P. Sundqvist wrote:
> Dear list,
>
> Is it possiblet to make implicit plots (i.e. ploting the curves
> described by equations) in MetaFun? I cannot find anything about them
> in the MetaFun manual.
>
> For example, in Mathematica I can write something like
>
Dear list,
Is it possiblet to make implicit plots (i.e. ploting the curves
described by equations) in MetaFun? I cannot find anything about them
in the MetaFun manual.
For example, in Mathematica I can write something like
ContourPlot[2 x^5 + x y + y^5 == 0, {x, 0, 2}, {y, -2, 1/2}]
to get the
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